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Agata [3.3K]
3 years ago
11

The answer choices are

Mathematics
1 answer:
Yuliya22 [10]3 years ago
7 0
I believe it’s C because none of the others are even close and the 3 and 7 add up correctly
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Please please please
matrenka [14]

Answer:

Step-by-step explanation:

These are logically difficult,  so it makes sense to me you're asking about this.

so  A = 1/2 (big arc - small arc)

and 360 = big arc + small arc

then

360 - small arc = big arc

so rewrite  the top equation

A = 1/2(360-small arc -small arc)

63 =  1/2( 360 - 2 small arc)

2* 63 = 360 - 2 small arc

126 = 360 - 2 small arc

2 small arc = 360-126

2small arc = 234

small arc = 234/2

small arc = 117

x = 117°

8 0
3 years ago
∠A and \angle B∠B are complementary angles. If m\angle A=(4x+24)^{\circ}∠A=(4x+24) ∘ and m\angle B=(3x-4)^{\circ}∠B=(3x−4) ∘ , t
Ostrovityanka [42]

Answer:

<h3>             m∠B = 26°</h3>

Step-by-step explanation:

∠A and ∠B being complementary means  m∠A + m∠B = 90°

4x + 24 + 3x - 4 = 90

7x + 20 = 90

  7x = 70

   x = 10

m∠B = (3•10 - 4)° = 26°

7 0
4 years ago
Please help i need to turn this in at 11:59 PM
vekshin1

Answer:

See explanation.

Step-by-step explanation:

To find the area of a parallogram, do A=Bh where a is the area, b is the base, and h is the height.

In this case, b is 9 cm while h is 6 cm. Do A=Bh by multiplying 9 cm by 6 cm. This will give us 54 cm².

The measurement we didn't use is the measure of the diagonal parts of the quadrilateral which, in this case, was 7.5 cm.

4 0
2 years ago
Read 2 more answers
Find parametric equations for the line through the point (0, 3, 2) that is parallel to the plane x + y + z = 5 and perpendicular
kozerog [31]
Hello : 
let A(0,3,2) and (Δ) this line , v vector   parallel to (<span>Δ).
M</span>∈ (Δ) : vector (AM) = t v..... t ∈ R

1 )    (Δ)  parallel to the plane x + y + z = 5 : let  : n an vector <span>perpendicular 
to the plane : n </span>⊥ v   ....   n(1,1,1) so : n.v =0  means : n.vector (AM) = 0
(1)(x)+(1)(y-3)+(1)(z -2) =0      ( vector (AM) = ( x, y -3 , z-2 )
x+y+z - 5=0 ...(1)

2)  (Δ) perpendicular to the line (Δ') : x = 1+t  , y = 3 - t , z = 2t :
vector (u) ⊥ v     .... vector(u) parallel to (Δ')  and vector(u) = (1 , -1 ,1)
vector (u) ⊥ vector (AM) means : 
(1)(x)+(-1)(y-3)+(2)(z -2) =0
x - y+2z - 1 = 0 ...(2)
so the system : 
x+y+z - 5=0 ...(1)
x - y+2z - 1 = 0 ...(2)
 (1)+(2) :   2x+3z - 6 =0
x = 3 - (3/2)z
subsct in (1) :    3 - (3/2)z  +y +z - 5 =0
y = 1/2z +2
let : z=t     
an parametric equations for the line (Δ) is :  x = 3 - (3/2)t
                                                                      y = (1/2)t +2
                                                                      z=t

verifiy : 
1) (Δ)  parallel to the plane x + y + z = 5 : 
(-3/2 , 1/2 ,1) <span>perpendicular to (1,1,1)
</span>because : (1)(-3/2)+(1)(1/2)+(1)(1) = -1 +1 = 0
2) (Δ) perpendicular to the line (Δ') :
 (-3/2 , 1/2 ,1) perpendicular to (1,-1,2)
because : (1)(-3/2)+(-1)(1/2)+(1)(2) = -2 +2 = 0
A(0, 3, 2)∈(Δ) : 
0 = 3-(3/2)t
3 = (1/2)t+2
2 =t
same :  t = 2

3 0
3 years ago
Write an algebraic expression for "the product of a number and 17."
jeka57 [31]
Let the number be x

then product of number and 17 would be written as 17x
4 0
3 years ago
Read 2 more answers
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