Answer:
Step-by-step explanation:
These are logically difficult, so it makes sense to me you're asking about this.
so A = 1/2 (big arc - small arc)
and 360 = big arc + small arc
then
360 - small arc = big arc
so rewrite the top equation
A = 1/2(360-small arc -small arc)
63 = 1/2( 360 - 2 small arc)
2* 63 = 360 - 2 small arc
126 = 360 - 2 small arc
2 small arc = 360-126
2small arc = 234
small arc = 234/2
small arc = 117
x = 117°
Answer:
<h3>
m∠B = 26°</h3>
Step-by-step explanation:
∠A and ∠B being complementary means m∠A + m∠B = 90°
4x + 24 + 3x - 4 = 90
7x + 20 = 90
7x = 70
x = 10
m∠B = (3•10 - 4)° = 26°
Answer:
See explanation.
Step-by-step explanation:
To find the area of a parallogram, do A=Bh where a is the area, b is the base, and h is the height.
In this case, b is 9 cm while h is 6 cm. Do A=Bh by multiplying 9 cm by 6 cm. This will give us 54 cm².
The measurement we didn't use is the measure of the diagonal parts of the quadrilateral which, in this case, was 7.5 cm.
Hello :
let A(0,3,2) and (Δ) this line , v vector parallel to (<span>Δ).
M</span>∈ (Δ) : vector (AM) = t v..... t ∈ R
1 ) (Δ) parallel to the plane x + y + z = 5 : let : n an vector <span>perpendicular
to the plane : n </span>⊥ v .... n(1,1,1) so : n.v =0 means : n.vector (AM) = 0
(1)(x)+(1)(y-3)+(1)(z -2) =0 ( vector (AM) = ( x, y -3 , z-2 )
x+y+z - 5=0 ...(1)
2) (Δ) perpendicular to the line (Δ') : x = 1+t , y = 3 - t , z = 2t :
vector (u) ⊥ v .... vector(u) parallel to (Δ') and vector(u) = (1 , -1 ,1)
vector (u) ⊥ vector (AM) means :
(1)(x)+(-1)(y-3)+(2)(z -2) =0
x - y+2z - 1 = 0 ...(2)
so the system :
x+y+z - 5=0 ...(1)
x - y+2z - 1 = 0 ...(2)
(1)+(2) : 2x+3z - 6 =0
x = 3 - (3/2)z
subsct in (1) : 3 - (3/2)z +y +z - 5 =0
y = 1/2z +2
let : z=t
an parametric equations for the line (Δ) is : x = 3 - (3/2)t
y = (1/2)t +2
z=t
verifiy :
1) (Δ) parallel to the plane x + y + z = 5 :
(-3/2 , 1/2 ,1) <span>perpendicular to (1,1,1)
</span>because : (1)(-3/2)+(1)(1/2)+(1)(1) = -1 +1 = 0
2) (Δ) perpendicular to the line (Δ') :
(-3/2 , 1/2 ,1) perpendicular to (1,-1,2)
because : (1)(-3/2)+(-1)(1/2)+(1)(2) = -2 +2 = 0
A(0, 3, 2)∈(Δ) :
0 = 3-(3/2)t
3 = (1/2)t+2
2 =t
same : t = 2
Let the number be x
then product of number and 17 would be written as 17x
