A=g
v=⌠g dt
v=gt+C, where C=v initial
v=gt+vi
h=⌠v dt
h=gt^2/2+vit+C, where C=h initial
h=gt^2/2+vit+hi
We are told that vi=42 ft/s, hi=0, and we know g≈-32 ft/s^2 so
h(t)=-16t^2+42t
The ball will hit the ground when h=0 so
-16t^2+42t=0
-2t(8t-21)=0, since t>0
8t-21=0
8t=21
t=21/8
t=2.625 sec
t≈2.6 sec (to nearest tenth of a second)
I think answer should be d. Please give me brainlest let me know if it’s correct thanks bye
525/1000 = 105/200 = 21/40
Thickness of the plate before polishing = 2.342
Thickness of the plate after polishing. = 2.087
How much was removed = 2.342- 2.087 = 0.255
Hence , the answer 0.255 which is option B
Answer:
3/32
Step-by-step explanation:
1 times 3= 3 and 8 times 4=32