Dive correct answers by total questions:
160/200 = 0.80
Multiply by 100 to get percent:
0.80 x 100 = 80%
6yd
8yd a =48sq yd (6×8=48)
4yd
12yd a=48sq yd (4×12=48)
4/5 x55
=4/5*55/1
=(4*55)/(5*1)
=220/5
=44/1
=44
Answer:
See proof below
Step-by-step explanation:
An equivalence relation R satisfies
- Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
- Symmetry: For all x,y, if xRy then yRx.
- Transitivity: For all x,y,z, If xRy and yRz then xRz.
Let's check these properties: Let x,y,z be bit strings of length three or more
The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.
If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.
If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.
Y2-y1/x2-x1= -47-(-7)/-19-(-9)= 4
