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Grace [21]
3 years ago
8

If the car spends no time going 35 miles per hour, about how long would the trip take? Round the answer to the nearest hundredth

. and explain
Mathematics
1 answer:
GrogVix [38]3 years ago
7 0
What’s the car ride hour
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Date
Brilliant_brown [7]

Answer:

The slope is \frac{1}{2} x so the line would go up one over two instead of down one over two, therefore the graph would look like this:

5 0
3 years ago
Read 2 more answers
An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,
butalik [34]

Answer:

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

Step-by-step explanation:

Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:

First airplane

r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t

Where t is the time measured in hours.

Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

s=\sqrt{r_{A}^{2}+r_{B}^{2}}

Rate of change of such distance can be found by the deriving the expression in terms of time:

\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }

Where \frac{dr_{A}}{dt} = 500\,\frac{mi}{h} and \frac{dr_{B}}{dt} = 550\,\frac{mi}{h}, respectively. Distances of each airliner at 2:30 PM are:

r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi

r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi

The rate of change is:

\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

6 0
3 years ago
Csc x= -√2 for π≤x≤3π/2
love history [14]

Answer:

A

Step-by-step explanation:

We can write this as Sinx by "flipping" the -\sqrt{2}.

So we will have:  Sin(x)=-\frac{1}{\sqrt{2} }

From basic trigonometry, we know the value of  \frac{1}{\sqrt{2}}  of sine is of the angle \frac{\pi}{4}

<em>But when is sine negative? </em>Either in 3rd or 4th quadrant. But the answer has to be between 0 and  \frac{3\pi}{2}, <em>so we disregard 4th quadrant.</em>

<em />

<em>To get the angle in 3rd quadrant, we add π to the acute angle of the first quadrant (which is π/4 in our case).</em><u><em> Thus we have:</em></u>

\frac{\pi}{4}+\pi\\=\frac{\pi +4\pi}{4}\\=\frac{5\pi}{4}

A is the right answer.

7 0
3 years ago
Tyler also wants to leave a tip for the server. How much do you think he should pay in all? Explain your reasoning.
Ludmilka [50]
Easy split the overall top
3 0
2 years ago
Can someone please tell me the ans of question no. 5, 7 and 12
uysha [10]

Step-by-step explanation:

Z²=x³

Z²=9³

Z= √9³

Z= 27

7 0
3 years ago
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