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serg [7]
3 years ago
5

Find the simple interest on $900 for 18 months at a rate of 9.5% per year

Mathematics
1 answer:
Anestetic [448]3 years ago
6 0
To get the simple interest, we must use the formula: I= (p)(r )( t)
So, in this one we need to multiply $900x18x9.% and the answer will be  $128.25. This is the amount of interest they are going to pay per year.
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Estimate using a rate per 100 of 74% of 315. 89% of 195
LiRa [457]
<span><span>1.       </span>Given numbers:
74 % of 315
89% of 195

now, let’s solve the first given numbers:
=> 74% of 315
=> 315 is the 100%
Let’s convert 74% into decimals
=> 74% = .74
=> 315 * .74 = 233.1, the value of 74% of 315
Let’s solve the second given:
=> 89% of 195
where 195 is the 100%
=> 89% = .89
=> 195 * .89
=> 173.55, the value of 89% of 195</span>



3 0
3 years ago
The area of a circular fountain is 121pi square feet. What is the diameter of the fountain?
Alla [95]

Answer:

22 feet

Step-by-step explanation:

Area of circle = pi(r²)

the square root of 121 is 11, so r = 11

d = 2r

d = 22

7 0
2 years ago
Hey if I could get some help it would be great
noname [10]

Answer:

One solution

Step-by-step explanation:

7 0
3 years ago
An architect makes a model of a new house. The model shows a tile patio in the backyard. In the​ model, each tile has length
zvonat [6]

The two ways to find the ratio of the length is to turn the inches into feet or the feet into inches

So the answer can be solved like this:

1/36ft to 1/4ft which is 9:1 (blueprint size to actual size)

or

1/3in to 3in which is also 9:1 (blueprint size to actual size)

3 0
3 years ago
Find the missing sides, and give the simplified form of the square root
Brilliant_brown [7]

Answer:

in the pics

Step-by-step explanation:

In case you are wondering, I used the pythagorean theorem. If you want to learn how to use it I suggest you google it, there are plenty of sites that explain how to use it.

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

7 0
3 years ago
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