ten times the smallest of three consecutive integers is twenty two more than three times the sum of the integers. find the integ
ers
1 answer:
Answer:
31, 32 and 33
Step-by-step explanation:
Mark these consecutive integers as (n-1), n and (n+1)
(n-1) is the smallest of them
Now write the equation
10 * (n-1) = 3 * (n-1 + n + n+1) + 22
10n - 10 = 3 * (n + n + n) + 22
10n - 10 = 3 * 3n + 22
10n - 10 = 9n + 22
10n - 9n = 22 + 10
n = 32
Now find these three integers
n-1 = 32 - 1 = 31
n = 32
n+1 =32 + 1 =33
You might be interested in
Here you go!! I hope this helps
Answer:
I hope this helps you're welcome
Answer:
x=3 cm
Step-by-step explanation:
x/3=5/5
x=3
2 times 4.95 equals 9.9
16.56 times 6 equals 99.36
add it up and it’s 109.26
Answer:
95
Step-by-step explanation:
Average =
Sum
Count
=
332
4
= 83