Answer:
16/64 simplified to lowest terms is 1/4
Step-by-step explanation:
Find the GCD (or HCF) of numerator and denominator
GCD of 16 and 64 is 16
Divide both the numerator and denominator by the GCD
16 ÷ 16
64 ÷ 16
Reduced fraction:
1/
4
The correct answers are a,b,e,f
Hello,
In order to exist ,k>=0
1) sin (180°+x)=-sin (x) ==>sin(203°)=-√k
2) cos² x +sin² x=1==>cos x=√(1+sin² x)=√(1+k)
3)tan (-x)=-tan (x) =-sin (x)/cos (x) =- √k/√(1+k)=√(k/(1+k))
X=5 and y= -2/3
That would be the answer in this situation
