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Korvikt [17]
3 years ago
13

Pls help me right now ​

Mathematics
1 answer:
Irina-Kira [14]3 years ago
6 0
Search the question on the internet and ask if which it is out of them both answers and there you go
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Draw the image of the following triangle after a dilation centered at the origin with a scale factor of 2.
Natasha_Volkova [10]
I really don’t know but I guess 2
5 0
2 years ago
A card is drawn at random from a well-shuffled pack of 52 cards. Find the probability that the card drawn is neither a red card
Reil [10]
Number of red cards including 2 red queens = 26
Number of black queens = 2
Therefore, number of red cards including 2 red queens and 2 black queens = 26 + 2 = 28
Number of cards neither a red card nor a queen = 52 - 28 = 24

P  =  \frac{ Number \: of \: favourable \: outcomes}{ Total \: numer \: of \: possible \: outcomes}

P (neither \: a \: red \: nor \: a \: queen \: card \: ) =  \frac{24}{52}  =  \frac{6}{13}
8 0
3 years ago
Plzzz hurry up and help me if A+B=45<br>prove that <br>(1+tanA)(1+tanB)=2​
Solnce55 [7]

Answer:

see explanation

Step-by-step explanation:

If A +B = 45° then tan(A+B) = tan45° = 1

Expanding (1 + tanA)(1 + tanB)

= 1 + tanA + tanB + tanAtanB → (1)

Using the Addition formula for tan(A + B)

tan(A+B) = \frac{tanA+tanB}{1-tanAtanB} = 1 ← from above

Hence

tanA + tanB = 1 - tanAtanB ( add tanAtanB to both sides )

tanA + tanB + tanAtanB = 1 ( add 1 to both sides )

1 + tanA + tanB + tanAtanB = 2

Then from (1)

(1 + tanA)(1 + tanB) = 2 ⇒ proven

7 0
3 years ago
Given two fair dice, find the probability of rolling a sum of 8 on the two dice.
bekas [8.4K]
With a dice right is it math I’m confused
8 0
3 years ago
Read 2 more answers
please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up​
babunello [35]

Answer:

y'' =12x^2 -72=0

And solving we got:

x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}

We can find the sings of the second derivate on the following intervals:

(-\infty Concave up

x=-\sqrt{6}, y =-180 inflection point

(-\sqrt{6} Concave down

x=\sqrt{6}, y=-180 inflection point

(\sqrt{6} Concave up

Step-by-step explanation:

For this case we have the following function:

y= x^4 -36x^2

We can find the first derivate and we got:

y' = 4x^3 -72x

In order to find the concavity we can find the second derivate and we got:

y'' = 12x^2 -72

We can set up this derivate equal to 0 and we got:

y'' =12x^2 -72=0

And solving we got:

x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}

We can find the sings of the second derivate on the following intervals:

(-\infty Concave up

x=-\sqrt{6}, y =-180 inflection point

(-\sqrt{6} Concave down

x=\sqrt{6}, y=-180 inflection point

(\sqrt{6} Concave up

8 0
3 years ago
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