Question

Please help asap solve x^4+5x^2+4=0

Answer 1

Answer:

$x=\pm i\text{ or }x=\pm2i$

Step-by-step explanation:

So we have the equation:

$x^4+5x^2+4=0$

Let's let u be equal to x². So:

$u^2+5u+4=0$

Factor:

$(u+1)(u+4)=0$

Zero Product Property:

$u+1=0\text{ or } u+4=0$

Subtract:

$u=-1\text{ or }u=-4$

Replace:

$x^2=-1\text{ or }x^2=-4$

Take square root:

$x=\pm\sqrt{-1}\text{ or }x=\pm\sqrt{-4$

Simplify:

$x=\pm i\text{ or }x=\pm2i$