The answer is 21.
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50%. students (in percent) who passed the second exam also passed the first exam.
Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.
Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.
Thus, both tests were passed by 40 of the 80 pupils who passed the second one:
40/80 = 1/2 = 50%.
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Step One
Begin by getting one side of the question equal to zero.
32x -4 = 4x^2 + 60 Add - 32x + 4 from both sides.
0 = 4x^2 + 60 - 32x + 4 Collect like terms.
0 = 4x^2 - 32x + 64
Step Two
For this question, you could divide both sides by 4. It just makes the steps later on easier.
0 = x^2 - 8x + 16
Step Three
Calculate the discriminate.
The discriminate is b^2 - 4*a*c
a = 1; b = -8; c = 16
b^2 - 4*a*c = (-8)^2 - 4*(1)(16) = 64 - 64 = 0
There is only 1 root. It is real and it is rational.
A <<<<< Answer
Answer:
d) one solution; (4, 1)
Step-by-step explanation:
It often works well to follow problem directions. A graph is attached, showing the one solution to be (4, 1).
_____
You know there will be one solution because the lines have different slopes. Each is in the form ...
y = mx + b
where m is the slope and b is the y-intercept.
The first line has slope -1 and y-intercept +5; the second line has slope 1 and y-intercept -3. The slope is the number of units of "rise" for each unit of "run", so it can be convenient to graph these by starting at the y-intercept and plotting points with those rise and run from the point you know.
A is not a line of symmetry