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Diano4ka-milaya [45]
3 years ago
12

Like y'all is so nice for helping me because this work is so hard so can yall help me and i will give barinlest☺️

Mathematics
1 answer:
ELEN [110]3 years ago
5 0

Answer:

The answer is A I hope it’s right

Step-by-step explanation:

405-319=86

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Fernando had to pay $1.40 in sales tax when he purchased a shirt . If the sales tax rate is 7% how much did his shirt cost
hjlf

Answer:

$20

Step-by-step explanation:

Work backwards so Price(.07) = $1.40 so x (.07) = 1.40, solving for x then

x = 1.4/.07 so x = 20

8 0
3 years ago
In the Ridgeland Park youth athletics program, 60% of athletes play baseball and 24% of athletes play baseball and basketball. W
scoundrel [369]
24% is the answer...Hope this helps
7 0
4 years ago
Read 2 more answers
In August, Ralph bought a new set of golf clubs that cost $565. The cost of the clubs was marked up to $650 in October. Which pr
BartSMP [9]

The percent of the original price, the new price is given as 86.9%

<u>Solution:</u>

Given, In August, Ralph bought a new set of golf clubs that cost $565.  

The cost of the clubs was marked up to $650 in October.  

We have to find which proportion can be used to find what percent of the original price the new price is, if p represents the unknown percent?

The formula is normally partial/whole equals to percentage/100.  In this case $565 is partial because the price increased.  

So it will be,

\frac{565}{650}=\frac{p}{100}

\begin{array}{l}{565 \times 100=p \times 650} \\\\ {650 p=56500} \\\\ {p=\frac{56500}{650}=86.9230}\end{array}

Whenever you get results like these, you just need to round to the nearest hundredths place, which is 86.9%.

Hence, the percentage is 86.9%

5 0
3 years ago
Use the definition of the derivative to differentiate f(x)= In x
WINSTONCH [101]

By def. of the derivative, we have for y = ln(x),

\displaystyle \frac{dy}{dx} = \lim_{h\to0} \frac{\ln(x+h)-\ln(x)}{h}

\displaystyle \frac{dy}{dx} = \lim_{h\to0} \frac1h \ln\left(\frac{x+h}{x}\right)

\displaystyle \frac{dy}{dx} = \lim_{h\to0} \ln\left(1+\frac hx\right)^{\frac1h}

Substitute y = h/x, so that as h approaches 0, so does y. We then rewrite the limit as

\displaystyle \frac{dy}{dx} = \lim_{y\to0} \ln\left(1+y\right)^{\frac1{xy}}

\displaystyle \frac{dy}{dx} = \frac1x \lim_{y\to0} \ln\left(1+y\right)^{\frac1y}

Recall that the constant e is defined by the limit,

\displaystyle e = \lim_{y\to0} \left(1+y\right)^{\frac1y}

Then in our limit, we end up with

\displaystyle \frac{dy}{dx} = \frac1x \ln(e) = \boxed{\frac1x}

In Mathematica, use

D[Log[x], x]

5 0
3 years ago
Find the missing length indicated​
Rina8888 [55]

Answer:

c = 175

Step-by-step explanation:

When the height of a right triangle is shown this way (at right angles with the hypotenuse, It can be found by using the way the hypotenuse is broken up. The following proportion works.

576/x = x / 49          Cross multiply

x^2 = 576 * 49

sqrt(x^2) = sqrt(576*49)

x = 24 * 7

x = 168

But that's not what you want (although it is close).

What you want is the hypotenuse to the small lower triangle

c = ?

a = 49

b = 168

c^2 =  49^2 + 168^2

c^2 = 2401 + 28224

c^2 = 30625

c = sqrt(30625)

c = 175

4 0
3 years ago
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