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Setler79 [48]
3 years ago
8

Express the percent as a decimal. 41%

Mathematics
2 answers:
nikklg [1K]3 years ago
8 0

Answer:

0.41

Step-by-step explanation:

41/100

0.41

hope it helps

Komok [63]3 years ago
4 0

Answer:

0.41

Step-by-step explanation:

Percentages, fractions, and decimals are tightly connected.

  • When breaking the meaning of "percent" down, you get "per" (for each) and "cent" ("hundred" in French), so a percent is always a number over 100.
  • A fraction is one number divided by another, a part of a whole.
  • A decimal is a number expressed with the base-ten system of counting.

This being said, if you get 41%, remember that you can write it as a fraction of the number over 100, which would be \frac{41}{100}. You can then turn it into a decimal*, which would be 0.41.

*when you have a two-digit whole number as the numerator of a fraction with denominator 100, the decimal form would just be 0. the numerator and the percent would be the numerator %. If the numerator is a whole one-digit number and the denominator is 100, the decimal form would be 0.0 the numerator, and the percent would still be just the numerator %.

  • e.g. for a fraction of \frac{17}{100}, the decimal is 0.17 and the percent is 17%.
  • e.g. for a fraction of \frac{3}{100}, the decimal is 0.03 and the percent is 3%.
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Answer:

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Step-by-step explanation

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Problem PageQuestion
krok68 [10]

Answer:

Jennifer's height is 63.7 inches.

Step-by-step explanation:

Let <em>X</em> = heights of adult women in the United States.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 65 inches and standard deviation <em>σ</em> = 2.4 inches.

To compute the probability of a normal random variable we first need to convert the raw score to a standardized score or <em>z</em>-score.

The standardized score of a raw score <em>X</em> is:

z=\frac{X-\mu}{\sigma}

These standardized scores follows a normal distribution with mean 0 and variance 1.

It is provided that Jennifer is taller than 70% of the population of U.S. women.

Let Jennifer's height be denoted by <em>x</em>.

Then according to the information given:

    P (X > x) = 0.70

1 - P (X < x) = 0.70

    P (X < x) = 0.30

⇒  P (Z < z) = 0.30

The <em>z</em>-score related to the probability above is:

<em>z</em> = -0.5244

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

          z=\frac{X-\mu}{\sigma}

-0.5244=\frac{x-65}{2.4}

          x=65-(0.5244\times 2.4)

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Thus, Jennifer's height is 63.7 inches.

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3 years ago
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Answer:

xdb bsbdb

Step-by-step explanation:

sdfbdfbbs

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