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3 years ago

What number could replace m below? 4/12 = 1/m

Mathematics

1 answer:

scZoUnD [109]3 years ago

4 0

Answer:

Step-by-step explanation:

4/12 = 1/3 yepppp djdkkdkdd

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A triangular prism has bases with three congruent sides, each measuring 4 feet. The height of each triangle is approximately 3.5

MAVERICK [17]

84 square feet I just took the test and got it right! :)

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4 years ago

WILL MARK BRAIN What is 1 and two-thirds minus 2 and one-third What is 1 2/3 - 2/13

shtirl [24]

$1\frac{20}{39}$

3 0

4 years ago

Melinda and paul shovel driveways and sidewalks in the winter as a way to earn extra money. together they shoveled 450 square fe

liubo4ka [24]

From my research the given equations are:
30x + 30y = 450

20x + 25y = 345

The problem asks to solve for the number of square feet Paul has shoveled more than Melinda. This can be solved by using the system of equations to solve for the values of x and y (the respective values of how each they have shoveled each).

Using the system of equations, the following values were obtained:
x = 6
y = 9

Therefore, Paul has shoveled 3 square feet per minute more than Melinda.

6 0

4 years ago

Read 2 more answers

Find the c.o.p (4,9) (4,12) (5,21)

pochemuha

Answer:

police

Step-by-step explanation:

5 0

3 years ago

A classmate plotted the following points:

irga5000 [103]

Answer:

D(-1,0)

Step-by-step explanation:

Plot points A(-3, 2), B(-1, 4), and C(1, 2) on the coordinate plane (see attached diagram).

Two sides AB and BC are of equal length and are perpendicular, because

$AB=\sqrt{(-3-(-1))^2+(2-4)^2}=\sart{(-2)^2+(-2)^2}=\sqrt{4+4}=2\sqrt{2}\ units\\ \\BC=\sqrt{(-1-1)^2+(4-2)^2}=\sart{(-2)^2+2^2}=\sqrt{4+4}=2\sqrt{2}\ units\\ \\\text{Slope AB}=\dfrac{4-2}{-1-(-3)}=\dfrac{2}{2}=1\\ \\\text{Slope BC}=\dfrac{2-4}{1-(-1)}=\dfrac{-2}{2}=-1\\ \\\text{Slope AB}\cdot \text{Slope BC}=1\cdot (-1)=-1\Rightarrow \text{lines AB and BC are perpendicular}$

If the quadrilateral ABCD has all sides perpendicular, then ABCD is a square. The diagonals of the square bisects each other. Find the coordinates of the point of intersection of these diagonals. This is the midpoint of segment AC:

$x=\dfrac{-3+1}{2}=-1\\ \\y=\dfrac{2+2}{2}=2$

If point O(-1,2) is the point of intersection of diagonals, then it is the midpoint of the diagonal BD. Find coordinates of point D:

$x_O=\dfrac{x_B+x_D}{2}\Rightarrow -1=\dfrac{-1+x_D}{2},\ -1+x_D=-2,\ x_D=-1\\ \\y_O=\dfrac{y_B+y_D}{2}\Rightarrow 2=\dfrac{4+y_D}{2}, 4+y_D=4,\ y_D=0$

Thus, D(-1,0)

7 0

4 years ago