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jeka94
3 years ago
10

Write code which takes two inputs from the user, a number of sides followed by a side length, then creates a regular polygon wit

h that number of sides and side length.Sample run:Type the number of sides:8Type a side length:7.5regular octagon with side length 7.5Hint: Make sure you use the right data types when taking user input.
Computers and Technology
2 answers:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

import java.util.Scanner;

public class Polygon {

       public static void main(String[] args) {

               Scanner sc = new Scanner(System.in);

               System.out.println("Type the number of sides:");

               int sides = sc.nextInt();

               System.out.println("Type a side length:");

               double length = sc.nextDouble();

               if (sides== 5){

                      System.out.println("Pentagon, length "+length);

               } else if (sides == 6){

                      System.out.println("Hexagon, length "+length);

               } else if (sides == 7){

                      System.out.println("Heptagon length "+length);

               } else if (sides == 8){

                       System.out.println("Octagon, length "+length);

                } else if (sides == 9){

                       System.out.println("Nonagon, length "+length);

                 } else if (sides == 10){

                       System.out.println("Decagon, length "+length);

} else if (sides == 11){

                       System.out.println("Undecagon, length "+length);

} else if (sides == 12){

                       System.out.println("Dodecagon, length "+length);

} else {

                       System.out.println("Please choose a valid number.");

               }

       }

}

Explanation:

The Java source code defines a class called 'Polygon' the main method of the class prompts for user inputs for the sides and length variables. The nested if-statement prints the type of polygon with respect to the number of sides.

Ahat [919]3 years ago
5 0

Answer:

i need free point sorry lol

Explanation:

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Answer:

True

Explanation:

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Are self driving cars essential for the future of transportation
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Write C++ code to open a document with the name Hello.txt, place the message "Hello, World!" in the document, and exit the docum
gavmur [86]

Answer:

#include<iostream>

#include<fstream>

using namespace std;

int main()

{

ofstream out;

out.open("Hello.txt");

out << "Hello, World!"<< endl;

out.close();

ifstream in;

in.open("Hello.txt");

while(in.good()){

   string line;

   in >> line;

   cout << line << endl;

   

}

in.close();

return 0;

}

Explanation:

Step 1:

Add all your preprocessor files directive,  #include is known as the preprocessor  is used to load files needed to run the code.

#include<iostream>: it provides basic input and output services for C++ programs.

#include<fstream>:used to open a file for writing and reading

using namespace std; means you'll be using namespace std means that you are going to use classes or functions (if any) from "std" namespace

Step 2:

ofstream out; <em>his  is  used  to  create  files  and   write data to the file</em>

out.open("Hello.txt"); <em>  a new file "HELLO.txt" has been created</em>

out << "Hello, World!"<< endl;  "<em>Hello World!" has now been writen to the file</em>

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<em>This second step opens a new file and writes hello world to the file then closes it.</em>

Step 3:

<em>ifstream in; ifstream in c++ is a stream class which stands for input file stream a  is used for reading data from file.</em>

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while(in.good()){

<em> in.good() is true if the previous read operation succeeded without EOF being encountered</em>

   string line; <em>It declares a string variable line</em>

   in >> line; <em>reads the data into the line variable</em>

   cout << line << endl; <em>Prints out the line</em>

<em>reopens the file and read the message into a string variable "line".  prints out line then exits out of the file.</em>

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Explanation:

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