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3 years ago

WILL GIVE BRAINLIEST! PLS HELP! 2, 6, 18… Find the 35th number in this pattern

Mathematics

2 answers:

inysia [295]3 years ago

8 0

Answer:

going by 2

Step-by-step explanation:

lilavasa [31]3 years ago

6 0

Answer:

3.3354363e+16

explanation:

the pattern here is the number times 3 until you reach the 35th times you've multiplied the previous number

2× 3= 6

6× 3= 18

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9- 3x - (-8y) + 9x - y Solve pleaseee

Yuki888 [10]

13x+9 I’m pretty sure is the answer

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3 years ago

Admission to the circus costs $4 plus $0.50 per ride ella spent $17.50 at the circus

harina [27]

Ella spent $13.5 dollars on rides. So she got in 27 rides.
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6 0

3 years ago

The proportion of students at a college who have GPA higher than 3.5 is 19%. a. You take repeated random samples of size 25 from

melomori [17]

Answer:

$\mu_{\hat{p}}=0.19$

$\sigma_{\hat{p}}=0.0785$

Step-by-step explanation:

We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-

$\mu_{\hat{p}}=p$

$\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}$

, where p=population proportion and n= sample size.

Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.

i.e. p= 19%=0.19

The for sample size n= 25

The mean and the standard error of the sampling distribution of the sample proportions will be :-

$\mu_{\hat{p}}=0.19$

$\sigma_{\hat{p}}=\sqrt{\dfrac{0.19(1-0.19)}{25}}\\\\=\sqrt{0.006156}=0.0784601809837\approx0.0785$

Hence , the mean and the standard error of the sampling distribution of the sample proportions :

$\mu_{\hat{p}}=0.19$

$\sigma_{\hat{p}}=0.0785$

8 0

3 years ago

1. Flight 202's arrival time is normally distributed with a mean arrival time of 4:30

Bezzdna [24]

Answer:

Step-by-step explanation:

1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min

By comparing P(0 ≤ Z ≤ 30)

P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)

Using Table

P(0 ≤ Z ≤ 1) = 0.3413

P(Z > 1) = (0.5 - 0.3413) = 0.1537

∴ P(Z > 45) = 0.1537

2) By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)

P(Z ≤ 15 - 30/15) = P(Z ≤ -1)

Using Table

P(-1 ≤ Z ≤ 0) = 0.3413

P(Z < 1) = (0.5 - 0.3413) = 0.1587

∴ P(Z < 15) = 0.1587

3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)

P(Z ≤ 60 - 30/15) = P(Z ≤ 2)

Using Table

P(0 ≤ Z ≤ 1) = 0.4772

P(Z > 1) = (0.5 - 0.4772) = 0.0228

∴ P(Z > 60) = 0.0228

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3 years ago

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algol [13]

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3 years ago