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Nookie1986 [14]

3 years ago

8

Max is going to eat either a slice of pie, an apple, or drink a cup of cider for a snack. He is also going to buy pumpkin or a h

at. How many different ways can max eat one snack or buy one item

2 answers:

MAXImum [283]3 years ago

6 0

Answer:

6 different ways

Step-by-step explanation:

pie, pumpkin

pie, hat

apple, pumpkin

apple, hat

cider, pumpkin

cider, hat

sattari [20]3 years ago

4 0

6 different ways! ....

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Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

Help me please ......,,,,

xz_007 [3.2K]

Answer:

Step-by-step explanation: for #1 its 6

for #2 it 12

#3 is 818

#4 is 423

#5 is 87

#6 is 500

hope this helped!

3 0

3 years ago

Read 2 more answers

An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach

Alexeev081 [22]

Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

a)

h(x) = -16x² +vx + h $_{o}$

here v represent velocity

$h_{o}$ represent initial height of launch

h(x) = -16x² + 192x + 208

b)

h(x) = -16x² + 192x + 208

here a = -16

b = 192

c = 208

x = -b/2a

= -192/2(-16)

= 6

plug this value in the equation

h(x) = -16(6)² + 192(6) + 208

= 784ft

e)

Plug h(x)=0 in the equation

0 = -16x² + 192x + 208

divide equation by -16

x² - 12x - 13 = 0

Factors

1x * -13x = -13

1x - 13x = -12

Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

(x+1)(x-13) = 0

x = -1

x = 13

Since time can not be negative so we will reject x = -1

3 0

3 years ago

Student scored in the 83rd

melamori03 [73]

Answer:b

Step-by-step explanation:

5 0

3 years ago

Can 5ft 9ft 14ft make a triangle?

ss7ja [257]

Answer:

Any dimensions can make a triangle, however

this does not make a right angled triangle.

Step-by-step explanation:

Determine the length of the hypotenuse of a right angle triangle with side lengths 5ft and 9ft by using the formula:

$a^2+b^2=c^2\\$

$\sqrt{a^2+b^2} = c$

$c=10.29$

This is not equal to 14ft.

6 0

3 years ago

Read 2 more answers