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joja [24]
3 years ago
15

Are the ratios 20:16 and 10:8 equivalent?​

Mathematics
1 answer:
lys-0071 [83]3 years ago
8 0
No they are not equivalent
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2x(3-x) what is the answer need help quick
Dvinal [7]
6x-2x^2 would be the answer 
3 0
3 years ago
Using the formula of a cone, express r in terms of V,h, and pie
monitta

Answer:

the correct answer would be r=\sqrt{x} \frac{3V}{h\pi }

Step-by-step explanation:

hope this helps

plz mark brainliest

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20-%201%20%7D%20%20-%20%20%5Cfrac%7B1%7D%7Bx%20-%201%7D%20" id
Degger [83]

Answer:

-x/x^2-1

Step-by-step explanation:

-x^2+x/x^3-x^2-x+1

x(-x+1)/(x+1)(x-1)(x-1)

-x/x^2-1

5 0
3 years ago
Which expression is equivalent to (x^4/3 x^2/3)^1/3?
KATRIN_1 [288]

Answer: x^{\frac{2}{3} }

Step-by-step explanation:

We have several properties of exponents in use here. The two that are used are:

(x^{a})(x^{b}) = x^{a + b} <em>(Exponents with the same base that are being multiplied together can have the exponents added)</em>

(x^{a})^{b} = x^{(a)(b)} <em>(A base raised to a power, and then raised to another power means that you can multiply the exponents to get the same result as doing inside operations and then outside operations)</em>

<em />

Let's apply it!

First, let's simplify what's inside the parenthesis.

x^{\frac{4}{3} } x^{\frac{2}{3} } <em>(Remember, they have the same base of "x", so we can add the exponents)</em>

x^{\frac{4}{3} + \frac{2}{3} } = x^{\frac{6}{3} } = x^{2}

Now we have (x^{2})^{\frac{1}{3} }. Let's use the second rule.

(x^{2})^{\frac{1}{3} } = x^{\frac{2}{3} }

Hope this helps! :^)

7 0
3 years ago
Cual es el numero que hace falta en la sucesión de 0,2,6,22_,114,202
Romashka-Z-Leto [24]

Answer:

86

Step-by-step explanation:

<h3>22+2²=22+64=86</h3>
6 0
3 years ago
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