To change the negative to a positive, just put the same number as into a fraction under 1 but without the negative sign:
11^-4 would become 1 / 11^4
Answer:
c) 4
Step-by-step explanation:
<u><em>The sum of two numbers is 14. The larger number minus three times the lesser number is -2</em></u>
<u><em /></u>
To solve this question, we need to write the statement mathematically;
Let the two numbers be x and y
"The sum of two numbers is 14" can be mathematically written as x+y = 14
and
"The larger number minus three times the lesser number is -2" can be mathematically written as x - 3y = -2
x + y = 14 ------------------(1)
x - 3y= -2 -------------------(2)
Subtract equation (2) from equation (1)
[x - x = 0 y - (-3y)=4y 14-(-2)=16]
4y = 16
To get the value of y divide both-side of the equation by 4
4y/4 = 16/4
y = 4
Substitute y=4 into equation (1)
x + y =14
x +4 =14
Subtract 4 from both-side of the equation
x + 4 -4 = 10]-4
x = 10
x=10 and y =4
Therefore the lesser number is 4
Problem 1
We'll use the product rule to say
h(x) = f(x)*g(x)
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
Then plug in x = 2 and use the table to fill in the rest
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)
h ' (2) = 2*3 + 2*4
h ' (2) = 6 + 8
h ' (2) = 14
<h3>Answer: 14</h3>
============================================================
Problem 2
Now we'll use the quotient rule
<h3>Answer: -2/9</h3>
============================================================
Problem 3
Use the chain rule
<h3>Answer: 12</h3>
Factoring:
FOIL (first, outer, inner, last) method
(a+b)(c+d) = 0
ac+ad+bc+bd = 0
Zeros:
(x+a)(x+b) = 0
x+a = 0, x= 0-a
x+b = 0, x= 0-b
