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3 years ago

Ms. Watson's recipe uses

Mathematics

2 answers:

Vikki [24]3 years ago

7 0

Answer: I think u have to take away 12 from 36

alexandr402 [8]3 years ago

3 0

Answer:

she will use 3 cups of milk

because 12 divided by 3 equals 12

Step-by-step explanation:

You might be interested in

Find the area and perimeter of a polygon with vertices located at A(-4,-8), B(4, -8), C(4, 0), D(0, 3), and E(-4,0).

AleksandrR [38]

Answer:

76 and 34

Step-by-step explanation:

See attached

As we see this is a polygon with sides of AB=BC=AE and CD=DE

Sides AB=BC=AE equal to 8
Sides CD=DE = $\sqrt{3^2 + 4^2}$ = 5

Area is the sum of areas of a square ABCE with side 8 and a triangle CDE with base of 8 and height of 3:

Area = 8*8 + 1/2*8*3 = 64 + 12 = 76
Perimeter = 8*3 + 5*2 = 24 + 10 = 34

3 0

3 years ago

I just need a quick answer please help me?

Feliz [49]

Answer:

x = 2.

y = 6.

Step-by-step explanation:

Consider the triangle on the left.

Because there are 2 equal angles at the vertex on the bottom right:

3/9 = x/(8 - x)

1/3 = x / (8 - x)

3x = 8 - x

4x = 8

x = 2 (answer).

Similarly, for the second triangle:

3/y = 2/4

3/y = 1/2

y = 6

(answer).

8 0

4 years ago

The expression wx7 gives the number of days in w weeks. What is the value of the expression when w=14?

Georgia [21]

98

(Spaceeeeeeee wasterrrrr ignore)

4 0

4 years ago

TIMED TEST!!

irina [24]

Answer:the answer is 0.14

Step-by-step explanation:

Because if you do 106 divided by 785 you get 0.1350 and you round

7 0

3 years ago

A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec

Paraphin [41]

Answer:

A. The solutions are $x=3i,\:x=-3i$ .

B. The factored form of the quadratic expression $x^2+9=(x-3i)(x+3i)$

Step-by-step explanation:

A. To find the solutions to the quadratic equation $x^2+9=0$ you must:

$\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}$

$x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i$

The solutions are:

$x=3i,\:x=-3i$

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor $x^2+9$ :

First, multiply the constant in the polynomial by $i^2$ where $i^2$ is equal to -1.

$x^2+9i^2$

Since both terms are perfect squares, factor using the difference of squares formula

$a^2-i^2=(a+i)(a-i)$

$x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)$

5 0

3 years ago