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3 years ago

Drag each expression to show whether it is equivalent to −1.3x−(−8.9x), −1.3x+(−8.9x), or neither.

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

3 0

Answer:

Neither

Step-by-step explanation:

−1.3x−(−8.9x) = −1.3x + 8.9x = 7.6x

−1.3x+(−8.9x) = −1.3x −8.9x = -10.2x

Answer: Neither

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Answer:

$z^{\frac{1}{3}}$

Step-by-step explanation:

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The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviat

aleksley [76]

Answer:

4.5 hour and 2 hour

Step-by-step explanation:

Given: The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviation of two hours.

To Find: If each time was increased by one hour, what would be the new mean and standard deviation.

Solution:

let the total numbers entries of hours in survey be = $\text{N}$

each entry in survey be = $\text{x}_{i}$

mean of survey is = $\mu$ = $3.5$ $\text{hours}$

standard deviation is = $\sigma$ = $2$ $\text{hours}$

if each entry in survey is increased by one hour then,

each new entry in survey is = $\text{x}_{i}+1$

the new mean is $\mu_{new}$ = $\frac{\text{sum of all hours}}{total number of entries}$

$\frac{\text{x}_{1} +1+\text{x}_{2}+1 +....+\text{x}_{N}+1 }{N}$

$\frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})+\text{N}\times1 }{N}$

$\frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})}{N}$ + $\frac{\text{N}\times1 }{N}$

$\mu_{new}$ = $\mu$ + 1= $4.5$ $\text{hours}$

now,

standard deviation is $\sigma_{new}=$ $\sqrt{\sum_{1}^{N}\frac{(\text{x}_{inew}-\mu_{new})^{2}}{N}}$

$\text{x}_{inew}= \text{x}_{i}+1$

$\mu_{new}=\mu+1$

putting values,

$\sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}+1-\mu-1)^{2}}{N}}$

$\sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}-\mu)^{2}}{N}}$ = $\sigma$

$\sigma_{new}$ =2

new mean and standard deviation are $4.5$ and $2$ $\text{hours}$

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