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2 years ago

Paying 20$ cashapp if you get this correct

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

3 0

Answer:

148⁰

Step-by-step explanation:

M< EDF = M< DFE (because the two angles are equal because the triangle has two equal sides)

2x + 8 = 3x + 4

8 – 4 = 3x - 2x

4=x or x=4

So M< EDF= 2x4+8 = 16⁰

So M< EDF + M< DFE= 32⁰

180⁰- 32⁰ = 148⁰

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An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

1 year ago

Factor −13 out of −13x−8.

Citrus2011 [14]

Answer:

i believe its x+5

Step-by-step explanation:

you add 13 to both numbers

8 0

3 years ago

Read 2 more answers

Priya's cat weighs 5 1/2 pounds and her dog weighs 8 1/4 pounds.

Lilit [14]

Answer: The cat is 2/3 times as heavy as the dog.

Step-by-step explanation:

The weight of Priya's cat = $5\frac{1}{2}\ pounds$

Now, $5\frac{1}{2}=\frac{11}{2}\ pounds$

The weight of her dog = $8\frac{1}{4}\ pounds$

$8\frac{1}{4}=\frac{33}{4}\ pounds$

Let cat is n times heavy as dog.

Then $n=\text{cat's weight}\div\text{dog's weight}$

$n=\frac{{11}{2}\div\frac{33}{4}\\\Rightarrow\ n=\frac{11}{2}\times\frac{4}{33}\\\Rightarrow\ n=\frac{2}{3}$

Hence, The cat is 2/3 times as heavy as the dog.

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3 years ago

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Romashka [77]

We let c represent the number of dozen cupcakes in which the problem says that the cost of each cupcake is $8 per dozen. In this case, the money earned by Eva should be a function of the number of dozen cupcakes. In this case, the expression that represents this is A. f(c) = c × 8

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3 years ago

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