Answer:
(6y-3)/7
Step-by-step explanation:
(2y-1/y²)(3y²/7) first simplify 3y²/y² =3
(2y-1)(3/7) =
(6y-3)/7
I do i posted a lot of math do the one that i posted a long time ago
Answer:

Step-by-step explanation:
<u>Equation of a Circle</u>
A circle of radius r and centered on the point (h,k) can be expressed by the equation

We are given the equation of a circle as

Note we have corrected it by adding the square to the y. Simplify by 3

Complete squares and rearrange:



We can see that, if r=4, then

Or, equivalently

There are two solutions for
:

Keeping the positive solution, as required:

Answer:
Between 15.95 ounces and 16.15 ounces.
Step-by-step explanation:
We have the following value m, being the mean, sd, being the standard deviation and n, the sample size:
m = 16.05
sd = 0.1005
n = 4
We apply the formula of this case, which would be:
m + - 2 * sd / (n ^ 1/2)
In this way we create a range, replacing we have:
16.05 + 2 * 0.1005 / (4 ^ 1/2) = 16.1505
16.05 - 2 * 0.1005 / (4 ^ 1/2) = 15.9495
Which means that 95% of all samples are between 15.95 ounces and 16.15 ounces.