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aleksandr82 [10.1K]
3 years ago
8

Solve for x 4x+8<2x+2

Mathematics
1 answer:
ipn [44]3 years ago
8 0

Answer:

x< -3

Step-by-step explanation:

4x+8<2x+2

4x+8-8<2x+2-8

4x<2x-6

4x-2x< -6

2x<-6

2x/2< -6/2

x< -3

hope it's helpful

THANK YOU.

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Which axiom is used to prove that the product of two rational numbers is rational
aliina [53]

Answer:

First, a rational number is defined as the quotient between two integer numbers, such that:

N = a/b

where a and b are integers.

Now, the axiom that we need to use is:

"The integers are closed under the multiplication".

this says that if we have two integers, x and y, their product is also an integer:

if x, y ∈ Z ⇒ x*y ∈ Z

So, if now we have two rational numbers:

a/b and c/d

where a, b, c, and d ∈ Z

then the product of those two can be written as:

(a/b)*(c/d) = (a*c)/(b*d)

And by the previous axiom, we know that a*c is an integer and b*d is also an integer, then:

(a*c)/(b*d)

is the quotient between two integers, then this is a rational number.

5 0
3 years ago
How many of the first 1000 positive integers are multiples of both 4 and 5 but not 6 ?
castortr0y [4]
Let's begin by breaking  each number down into its prime factors:    4 = 2 x 2    5 = 5    6 = 2 x 3 Next, let's determine the Lowest Common Multiple (LCM) of the numbers 4, 5, and 6 by multiplying all common and unique prime factors of each number:    common prime factors: 2    unique prime factors:  2,5,3    LCM = 2 x 2 x 5 x 3 = 60 Next, let's determine how many times 60 goes into 10,000 (excluding remainder):    10,000/60 = 166 and 2/3    Multiples of ALL 3 numbers (4,5,6) = 166  Next, let's determine the Lowest Common Multiple (LCM) of the numbers 4 and 5 by multiplying all common and unique prime factors of each number:    common prime factors:  none
    unique prime factors:  2 x 2 x 5
    LCM = 2 x 2 x 5 = 20 Next, let's determine how many times 20 goes into 10,000:
    10,000/20 = 500
    Multiples of BOTH numbers (4 and 5) = 500 Finally, let's subtract the multiples of ALL three numbers (4,5,6) from the multiples of BOTH numbers (4 and 5) to get our answer:   Multiples of ONLY numbers 4 and 5 (excluding 6):       500 - 166 = <span>334</span>
5 0
3 years ago
What are two ways to write 2a-18 in words
Rashid [163]

Two A minus eighteen

eighteen minus Two A

6 0
3 years ago
One out of 23 high school ball players plays college ball. One out of 35 college players plays professional ball. What fraction
Gnoma [55]

Answer:

\frac{35}{23} is the required fraction.

Step-by-step explanation:

We have  been given  that  23 high school ball players plays college ball.

And 35 college players plays professional ball  

So we need to find fraction of high school players professional ball

\frac{35}{23} is the required fraction.


6 0
3 years ago
What is the solution to the inequality?
Pavel [41]
The steps to solving an inequality are: add or subtract from each side - multiply or divide both sides - simplify. 

5x + 8 > -12
5x > -12 - 8
5x > -20
x > -20/5
x > -4

The answer is: x > -4
8 0
3 years ago
Read 2 more answers
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