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3 years ago

A + b - b = what is it plzz help

Mathematics

1 answer:

enot [183]3 years ago

4 0

Answer:

a + b - b = a

Step-by-step explanation:

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EVALUATE !!!! ILL GIVE YOU BRAINLIST HAVE TO GET IT RIGHT !!!!

elena-s [515]

Answer:

Step-by-step explanation:

$nxy\div m\\\\n =3/4\\x =8\\y =6\\m=3\\\\\frac{3}{4} \times 8 \times 6 \div 3\\\\\mathrm{Divide\:the\:numbers:}\:6\div \:3=2\\=\frac{3}{4}\times \:8\times \:2\\\\\mathrm{Convert\:element\:to\:fraction}:\quad \:8=\frac{8}{1}\\=2\times \frac{3}{4}\times \frac{8}{1}\\\\\mathrm{Convert\:element\:to\:fraction}:\quad \:2=\frac{2}{1}\\=\frac{3}{4}\times \frac{8}{1}\times \frac{2}{1}\\\\Multiply\:fractions\\=\frac{3\times \:8\times \:2}{4\times \:1\times \:1}\\\\=\frac{48}{4}\\\\Simplify\\=12$

8 0

3 years ago

Which of the following points is the solution of the quadratic equation:3x^2-5x-2=0

Maslowich

Answer:

x1 = 2

x2 = -1/3

Step-by-step explanation:

3x^2-5x-2=0

D=25-4*(-2)*3 = 25 + 24 = 49 --> sqrt 49 = 7

x1 = 5 + 7 / 2*3 = 2

x2 = 5 - 7 / 2*3 = -1/3

7 0

3 years ago

Evaluate the permutation P(36,19)=____

kondaur [170]

Easy

nPr= $\frac{n!}{(n-r)!}$
here
36P19= $\frac{36!}{(36-19)!}=$
$\frac{36!}{(17)!}=$
$\frac{36*35*34*33*32*31*30*29*28*27*26*25*24*23*22*21*20*19*18}{1}=$
1045843337171591729971200000

6 0

3 years ago

3/4 x 3 2/5 - 5/5(find the value of each of the following)

Triss [41]

The value of the given expression is $\frac{-13}{20}.$

Solution:

Given expression is $\frac{3}{4} \times3\frac{2}{5}-\frac{5}{5}$ .

Let us first convert mixed fraction into improper fraction.

$3\frac{2}{5}=\frac{(3\times5)+2}{5}=\frac{17}{5}$

Substitute this in the given expression.

$\frac{3}{4} \times3\frac{2}{5}-\frac{5}{5}=\frac{3}{4} \times\frac{7}{15}-\frac{5}{5}$

$=\frac{21}{60}-\frac{5}{5}$

To simplify the above expression, 21 and 60 are cancelled by 3.

$=\frac{7}{20}-\frac{1}{1}$

Do cross multiplication to make the denominator same.

$=\frac{7}{20}-\frac{20}{20}$

$=\frac{7-20}{20}$

$=\frac{-13}{20}$

The value of the given expression is $\frac{-13}{20}.$

7 0

3 years ago

How do you solve for sides a and b of a triangle when you know the value of c?

sasho [114]

Assuming you have some angle measures, you could use the Law of Sines to solve for the missing side lengths, which states that,
$\frac{a}{sinA}= \frac{b}{sinB}= \frac{c}{sinC}$ ,
where a, b, and c correspond to the given sides you have, and A, B, and C represent the angles you have.

In this scenario, you would have to have the values for c (which we do), and have the angle measure of C. In addition, we would also need an angle measure that is either A or B.

Hope this helps a bit!

:)

7 0

3 years ago