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scoray [572]
2 years ago
6

Carlos buys a phone that cost $250. He pays a monthly rate of $75. What is the independent variable of this function ?

Mathematics
1 answer:
erastova [34]2 years ago
7 0

Answer: 250+75x

Step-by-step explanation: 250 is the flat charge on the phone, and he pays 75 dollars as a monthly rate. x represents the amount on months.

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When an object is dropped from a building (height 1450 feet )
Law Incorporation [45]

Given

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Evaluate P(5), as shown below

\begin{gathered} P(5)=-16*5^2+1450 \\ \Rightarrow P(5)=-400+1450=1050 \end{gathered}

Therefore, the answer is 1050ft.

7 0
1 year ago
A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

4 0
3 years ago
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As i said before put the center instead of (h,k) in the general formula and put r=1 
so (x-(-2))^2 + (y-(-5)^2 = 1 
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