Answer:
14 and 4/1000 or 14004/1000
Step-by-step explanation:
1*10+3*1+4*(1/1000)
First i like to separate the equation by PEMDAS or order of operations. First is parentheses, which is the fraction. Then is exponents. There is none. Then multiplication and division so u solve 1*10, 3*1 and 4*1/1000.
This is the updated equation: 10+4+(4/1000)
Next you do subtraction and addition. The order does not matter if there's only addition. If there is subtraction u solve by the order of the equation. SO in this step we solve 10+4+(4/1000)
Here is the updated version: 14+(4/1000)
Then u add that which is 14 and 4/1000 or you can do 14004/1000
I think it is 24...Im not sure tho
Answer:
6^2
Step-by-step explanation:
We know a^b / a^c = a^(b-c)
6^5 / 6^3 = 6^(5-3) = 6^2
<h3>Answer: C) none of the equations are identities</h3>
If you plugged theta = 0 into the first equation, then you would have
sin(45) + cos(45) = sin(0) + cos(0)
sqrt(2) = 1
which is a false equation. We don't have an identity here.
The same story happens with the second equation. Plug in theta = 0 and it becomes
cos(60) - sin(60) = cos^2(0) + tan(0)
1/2 - sqrt(3)/2 = 1 + 0
-0.37 = 1
which is false.
