Answer:
6(3d+2)
Step-by-step explanation:
For combining like terms: it is 7z
Solution: We are given:
![\mu=0.33, \sigma =0.7](https://tex.z-dn.net/?f=%5Cmu%3D0.33%2C%20%20%5Csigma%20%3D0.7)
Let
be the weight (oz) of laptop
We have to find ![P(x>32)](https://tex.z-dn.net/?f=P%28x%3E32%29)
To find the this probability, we need to find the z score value.
The z score is given below:
![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
![=\frac{32-33}{0.7}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B32-33%7D%7B0.7%7D)
![=-1.43](https://tex.z-dn.net/?f=%3D-1.43)
Now, we have to find ![P(z>-1.43)](https://tex.z-dn.net/?f=P%28z%3E-1.43%29)
Using the standard normal table, we have:
![P(z>-1.43)=0.9236](https://tex.z-dn.net/?f=P%28z%3E-1.43%29%3D0.9236)
0.9236 or 92.36% of laptops are overweight
Answer:![\frac{253}{44}](https://tex.z-dn.net/?f=%5Cfrac%7B253%7D%7B44%7D)
Step-by-step explanation:
ignore the "at the instant the man is 30 feet away" part, set it as X and the man's shadow as Y.
Similar triangles so we can do
.
Solve for it we get 44y = 6x
Differentiate relative to time t, we get 44y' = 6x'.
change in x (x') is equal to 5. And we get the answer y' =
.
the
ft/sec is the rate of which the length of the shadow is changing. add 5 to it for the rate of the tip of his shadow moving away from the tower.
Answer:
BCDA is equivalent to FGHE
A is equivalent to angle E
B is equivalent to angle F
C is equivalent to angle G
D is equivalent to angle H
Step-by-step explanation:
1st step is just figuring out which sides corresponds with which.
A is equivalent to angle E
B is equivalent to angle F
C is equivalent to angle G
D is equivalent to angle H
On the last one I am confused by what it is asking, but here is what I think:
The scale factor from the big figure to the small figure is 1.5 because of 15/10=1.5
12/8=1.5 and so on.