Question

What is the equation of the line parallel to the one graphed below that passes through the point (2,5)?

Answer 1

1) Obtain the slope of the line graphed

The formula for the slope is m = rise / run = Δy / Δx

The origin of the graph is not well defined, but it is shown that the line passes through the points (0,-2) and (2,10)

That means m = (10 - (-2) ) / (2 - 0) = 12 / 2 = 6

2) The slope of any parallel line is the same: 6

3) Use the slope-point equation to find the final equation: (y - b) = m (x - a)

point (a,b) = (2,5)

m = 6

=> y - 5 = 6 (x - 2)

=> y - 5 = 6 x - 12

=> y = 6x - 12 + 5

=> y = 6x - 7

Therefore, the answer is the option D. y = 6x - 7