Answer:
Van = 18
Bus = 58
Step-by-step explanation:
Let v be the number of students carried by each van.
Let b be the number of students carried by each bus.
We know the following:
![$\left\{{{16v+8b=752}\atop{5v+5b=380}}$](https://tex.z-dn.net/?f=%24%5Cleft%5C%7B%7B%7B16v%2B8b%3D752%7D%5Catop%7B5v%2B5b%3D380%7D%7D%24)
Solve the second equation for b:
![$5v+5b=380$](https://tex.z-dn.net/?f=%245v%2B5b%3D380%24)
![$5b=380-5v$](https://tex.z-dn.net/?f=%245b%3D380-5v%24)
![$b=76-v$](https://tex.z-dn.net/?f=%24b%3D76-v%24)
Replace b with (76 – v) in the first equation:
![$16v+8b=752$](https://tex.z-dn.net/?f=%2416v%2B8b%3D752%24)
![16v+8(76-v)=752](https://tex.z-dn.net/?f=16v%2B8%2876-v%29%3D752)
![16v+608-8v=752](https://tex.z-dn.net/?f=16v%2B608-8v%3D752)
![8v+608=752](https://tex.z-dn.net/?f=8v%2B608%3D752)
![8v=144](https://tex.z-dn.net/?f=8v%3D144)
![v=18](https://tex.z-dn.net/?f=v%3D18)
Therefore, each van can carry 18 students. Each bus, then, can carry 76 – v = 76 – 18 = 58.
To verify:
High School A had 16 vans and 8 buses equaling (16 × 18) + (8 × 58) = 288 + 464 = 752. That is correct.
High School B had 5 vans and 5 buses equaling (5 × 18) + (5 × 58) = 90 + 290 = 380. That is correct.
Answer:
b) 10 to 20
Step-by-step explanation:
You have to multiply each of the given numbers by 4, and add 8 to that result.
So:
And 60 is between the result of <u>10 and 20</u>, so that's the interval you have to select.
<em>The correct answer is b) 10 to 20</em>