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2 years ago

Need helpp fastt plss will give brainliest to who is correct plss helpp

Mathematics

1 answer:

statuscvo [17]2 years ago

6 0

Answer: it would be c

Step-by-step explanation: I AINT NEVER SEEN TWO PRETTY BESTFRIENDS ALWAYS ONE OF THEM GOTTA BE UGLY....

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Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

X+9=24 how to solve for x

rodikova [14]

You can easily do just one step to get the value of x.

x + 9 =24 subtract 9 from both sides

x + 9 - 9 = 24 - 9

Simplify:

x = 15

I hope I helped you.

5 0

3 years ago

Read 2 more answers

How do you solve for x in a math question like this 5+4x=54-3x?

Bas_tet [7]

To solve for x, first you need to isolate all x terms on the same side so:

you start with 5 + 4x = 54 - 3x

subtract 5 from both sides to get 5 onto the left side

now you should have 4x = 49 - 3x

now add 3x to both sides to get 3x onto the right side

now you should have 7x = 49

now that you have your x on one side you can solve this like a regular one step equation and divide both sides by 7

this leads you to your answer of x = 7

hope this helps!

6 0

3 years ago

Read 2 more answers

What is a - 5 - 6a + 3

Yakvenalex [24]

Answer:

-7-5a

Step-by-step

i simplified it if thats what it meant

4 0

3 years ago

– 42 – 54 + 96 = what is the answer

mart [117]

Answer:

Answer:the answer is zero 

Answer:the answer is zero Step-by-step explanation:

Answer:the answer is zero Step-by-step explanation:when we add -42 and -54 the answer we get is -96. -96and +96 cut each other and then the answer is zero 

 $- 42 - 54 + 96 = 0$ 

6 0

2 years ago