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bagirrra123 [75]
3 years ago
7

at the start of the shift your part counter reads 250 at the end of the shift the part counter reads 1075 how many parts did you

produce
Mathematics
1 answer:
Luden [163]3 years ago
5 0
This can be mathematically expressed to
 250 + X  = 1075
where X represents the parts you produce before the shift ends
Transpose 250 to the other side by subtracting each side by 250
Thus, it goes like this
X = 1075 - 250
X = 825

You produced 825 parts in the middle of the shift.

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Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20
vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of y=f(x) is a vertical has an asymptote at x=a if at least one of the following statements is true:

1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty

The function is:

f(x)=\frac{x^2+7x+10}{x^2+9x+20}

First of all, let't factor out:

f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq  5

From here:

\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty

\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty

Accordingly:

x=-4 \ is \ a \ vertical \ asymptote \ for \\ \\ f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20}

<h2>Learn more:</h2>

Vertical and horizontal asymptotes: brainly.com/question/10254973

#LearnWithBrainly

5 0
3 years ago
Hey can someone help me out thank! :D ITS DUE TODAY PLZZZ!!!!
Pani-rosa [81]

Answer:

Hey can someone help me out thank! :D ITS DUE TODAY PLZZZ!!!!

1. Use the integer multiplication facts in their integer bubble to create six related integer division facts.

2.The quotient of any two integers (with a non zero divisor) will be a rational number. If and are integers, then - (p/q)= (---)=(----)

3. Mrs. McIntire, a seventh-grade math teacher, is grading papers. Three students gave the following responses to the same math problem: 1/-2 -(1/2) -1/2

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Step-by-step explanation:

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Step-by-step explanation:

3 0
3 years ago
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eduard

.186915888

that is the answer

if I meant 2.675 divided by .5 it is 5.35

7 0
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I need help finding the slope
lorasvet [3.4K]

Answer:

slope = 1

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (1, 1) and (x₂, y₂ ) = (2, 2) ← 2 ordered pairs from the table

m = \frac{2-1}{2-1} = \frac{1}{1} = 1

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