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3 years ago

HELP!!! Need to finish this today! Overdue! Will mark you branliest...your help will be greatly appreciated :)

Mathematics

2 answers:

Phantasy [73]3 years ago

7 0

SSS, because all of the sides are the same ; AC = BD , AB = CD , and they both share side BC

u have got this !! dont stress too much :(

azamat3 years ago

6 0

Answer:

C. SAS

Step-by-step explanation:

If you look at both of the triangles carefully, you will see that both side AB and side DC have the same amount of lines. Since they have the same sides, the angle that they share would equal each other as well. The last side is obviously equal to each other because they are the same.

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High school play at least once were. This is 70% of the students at the school how many students are at the school

bogdanovich [222]

U just divide 70 and 45 and u get your answer

7 0

3 years ago

What is the initial value in the function 2x + 3y = 6?

Galina-37 [17]

THE INITIAL VALUE IN THE FUNCTION ARE X=0 AND Y=2 OR X=3 AND Y=0.

Step-by-step explanation:

The initial value of the line segment is the value at which X=0 .

X=0 means nothing but a Y-intercept.

Now set X=0, in the function 2x+3y=6

2(0)+3y=6.

3y=6.

Therefore Y=2

so (0,2) is one point on the graph or line segment.

similarly considering X=3 in the line segment and that means Y=0.

Y=0 indicates X-intercept.

substituting X=3 in the function

2(X)+3(0)=6

2X=6

Therefore X=3

so (3,0) is another point on the line segment or graph.

4 0

4 years ago

If I got a 35% out of 20 questions and Im going to get half credit in the 13 problems I got wrong what is going to be my percent

dsp73

Answer:

Step-by-step explanation:

So since each question is 5% (100/20=5)

we can do ((13*5)/2) because of half credit we divide by two

now we get 32.5% back

32.5%+35%=67.5%

unless of course of extra points on other assignments, the highest grade you can get in that class (if every other thing is a 100%) is an 87 if im not mistaken.

7 0

3 years ago

(1 point) A bucket that weighs 3.6 pounds and a rope of negligible weight are used to draw water from a well that is 78 feet dee

Deffense [45]

Answer:

The total work done in pulling the bucket to the top of the well is approximately 3,139.1 ft·lb

Step-by-step explanation:

The given parameters are;

The mass of the bucket, W = 3.6 pounds

The depth of the well, h = 78 feet deep

The mass of water in the bucket = 38 ponds

The rate at which the water is pulled up = 2.9 feet per second

The rate at which water is leaking from the bucket, $\dot m$ = 0.1 pounds per second

We separate and find the work done for lifting the bucket and the water individually, then we add the answers to get the solution to the question as follows;

The work done in lifting bucket empty from the well bottom, $W_b$ = W × h

∴ $W_b$ = 3.6 pounds × 78 feet = 280.8 ft-lb

The work done in lifting bucket empty from the well bottom, $W_b$ = 280.8 ft-lb

The time it takes to lift the bucket from the well bottom to the top, 't', is given as follows;

Time, t = Distance/Velocity

The time it takes to pull the bucket from the well bottom is therefore;

t = 78 ft./(2.9 ft./s) ≈ 26.897

The time it takes to pull the bucket from the well bottom to the top, t ≈ 26.897 s

The mass of water that leaks out from the bucket before it gets to the top, m₂, is therefore;

m₂ = $\dot m$ × t

∴ m₂ = 0.1 lbs/s × 26.897 s = 2.6897

The mass of the water that leaks, m₂ = 2.6897 lbs

The mass of water that gets to the surface m₃ = m - m₂

∴ m₃ = 38 lbs - 2.6897 lbs ≈ 35.3103 lbs

Given that the water leaks at a constant rate the equation representing the mass of the water as it is lifted can b represented by a straight line with slope, 'm' given as follows;

The slope of the linear equation m = (38 lbs - 35.3103 lbs)/(78 ft. - 0 ft.) = 0.03448 $\overline 3$ lbs/ft.

Therefore, the equation for the weight of the water 'w' can be expressed as follows;

w = 0.03448 $\overline 3$ ·y + c

At the top of the well, y = 0 and w = 38

∴ 35.3103 = 0..03448 $\overline 3$ × 0 + c

c = 35.3103

∴ w = 0.03448 $\overline 3$ ·y + 35.3103

The work done in lifting the water through a small distance, dy is given as follows;

(0.03448 $\overline 3$ ·y + 38) × dy

The work done in lifting the water from the bottom to the top of the well, $W_{water}$ , is given as follows;

$W_{water} = \int\limits^{78}_0 {0.03448\overline 3 \cdot y + 35.3103 } \, dy$

$\therefore W_{water} = \left [ {\dfrac{0.03448\overline 3 \cdot y^2}{2} + 35.3103 \cdot y\right ]^{78}_0$

$W_{water}$ = (0.034483/2 × 78^2 + 35.3103 × 78) - (0.034483 × 0 + 38 × 0) ≈ 2,859.1

The work done in lifting only the water, $W_{water}$ ≈ 2,859.1 ft-lb

The total work done, in pulling the bucket to the top of the well, W = $W_b$ + $W_{water}$

∴ W = 2,859.1 ft.·lb + 280.8 ft.·lb ≈ 3,139.1 ft·lb

The total work done, in pulling the bucket to the top of the well, W ≈ 3,139.1 ft·lb.

6 0

3 years ago

What number represents an elevation of 80 feet below sea level

Snowcat [4.5K]

Answer:

-80

Step-by-step explanation:

The answer is -80 because 80 feet below sea level would be a negative number. So you just add a negative sign to 80 and voila! You get the answer. Your welcome, by the way!

7 0

3 years ago