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max2010maxim [7]
3 years ago
11

The ratio of dark chocolate candies to white chocolate candies is 3 to 2. There are 18 pieces of dark chocolate. How many pieces

of white chocolate are there?
Mathematics
1 answer:
ch4aika [34]3 years ago
4 0

there are 18 pieces of dark chocolate and the ratio of dark and white is 3:2 so we can divide 18 by 3.

18/3 = 6.

This means the ratio of dark chocolate to white as a 1:1 ratio would be 6:6 so we can multiply 6 by 2 to give us the total amount of pieces of white chocolate.

6*2 = 12.

Therefore there are 12 white chocolate pieces.

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Please help me with this question. I will mark you brainliest. ​
solong [7]

<u>Answer:</u>

<em>Option D : $153</em>

<u>This is how I got that:</u>

9:30 AM to 1:15 PM = 3 hours and 45 minutes

The first hour charges $15 and for the remaining 2 hours and 45 minutes

Mr. Anand is charged 36$. Remember it says that each additional hour <em>or part thereof, </em>so the 2 hours and 45 minutes is considered 3 hours.

So our total for one paddle boat is <u>$51 </u>

<u />

But Mr. Anand hired <em>three</em> boats so we simply times 51 by 3 and get our solution to the problem:

<u>Mr. Anand must pay $153 or Option D</u>

<u></u>

<em>~That's All Folks~</em>

<em>-Siascon</em>

4 0
2 years ago
I'm not sure to use 6 or 10 for a side length​
dlinn [17]

Answer:

10

Step-by-step explanation:

6 is the width not the length

6 0
3 years ago
Simplify x + 4 - 5x - 2.
Ilia_Sergeevich [38]
X+2-5x is the answer
8 0
2 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
2 years ago
3+n=7<br> 13.75e+39.50n=122.00<br><br> Plzzzz help I will mark your brainliest plzzz help I need it
vitfil [10]
The first one is 4 and the last one is 2.14237024 u can put all of that in if u want
6 0
2 years ago
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