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3 years ago

If you were to too a dice one time what is the odds of rolling a number less than three?

Mathematics

1 answer:

Doss [256]3 years ago

4 0

Answer:

1/3 or 33.33%

Step-by-step explanation:

A regular dice has 6 sides each with a single number from 1 to 6. Therefore, there are a total of 6 possible outcomes. Out of all of these only two outcomes are actually less than three and those are the numbers 1 and 2. Meaning, that if the dice were rolled only a single time then the probability of rolling a number less than 3 would be 2/6 or 1/3 (simplified). As a percentage, this probability would be 33.33%

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Helpppppppppppppppppppppppppp

avanturin [10]

Answer:

1/125, 1/625, 1/3125

Step-by-step explanation:

a8=25*(1/5)^7=25/78125=1/3125

5 0

3 years ago

A local high school held a two-day fundraiser selling lunches. The equations shown represent the amount of money the school coll

Over [174]

Answer:

Step-by-step explanation:

The two equations appear to be ...

12x +4y = 152
32x +12y = 420

These can be solved for y using Cramer's rule:

y = (152(32) -420(12))/(4(32) -12(12)) = -176/-16 = 11

The cost of the vegetarian lunch is 11.

_____

<em>Comment on Cramer's Rule</em>

For equations ...

ax +by =c

dx +ey = f

The solutions are ...

x = (bf -ey)/(bd -ea)

y = (cd -fa)/(bd -ea) . . . . note the denominators are the same expression

Once you memorize the pattern of products, this can be the simplest way to solve a pair of equations--especially if you only need one of the variable values.

6 0

3 years ago

Does anyone know the answer to this!?

PolarNik [594]

Answer:

$|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

Step-by-step explanation:

You can use these Cramer's formulas to solve for x and y:

$x=\dfrac{|A_x|}{|A|},\\ \\y=\dfrac{|A_y|}{|A|},$

where

$|A|=\left|\begin{array}{cc}12&-13\\ \\17&-22\end{array}\right|\\ \\ \\|A_x|=\left|\begin{array}{cc}7&-13\\ \\-51&-22\end{array}\right|\\ \\ \\|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

So,

$|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

4 0

3 years ago

Jose is a botanist studying production of coconuts by two different groups of his

Colt1911 [192]

Answer: 132

Step-by-step explanation:

Since we are informed that Group 1 of trees produced 25 percent more coconuts than Group 2 did and that Group 1 produced 165 coconuts, the number of coconuts that Group 2 produce will be:

= [100 / (100 + 25)] × 165

= 100/125 × 165

= 0.8 × 165

= 132

Group 2 produced 132 coconuts.

5 0

3 years ago

A scatter plot is shown below:

algol [13]

C)
It’s far off from most of the points

5 0

3 years ago

Read 2 more answers