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sveta [45]
3 years ago
7

Given that ABCD is a rhombus, what is the value of x?

Mathematics
1 answer:
choli [55]3 years ago
8 0

Answer:

A. 19.5

Step-by-step explanation:

Diagonals of a rhombus intersect at right angles. Therefore the angle opposite to AD = 90°.

Thus:

90° + x + 3x + 12 = 180° (sum of ∆)

Add like terms

102 + 4x = 180

Subtract 102 from each side

4x = 180 - 102

4x = 78

Subdue both sides by 4

x = 19.5

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Answer:

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x^2-3^2>0

(x+3)(x-3)>0

(x+3)>0 and (x-3)>0

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2. x2 - 8x + 12 > 0

   x^2 - 8x  +12>0

   x^2 -2x -6x +12 >0   (-8x is replaced by (-2x) + (-6x) )

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4. x2 + 3x - 20 >= 3x + 5

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      (x-5)(x+5)>=0

(x-5)>=0  and (x+5)>=0

  x>=5    and x>=-5

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3 years ago
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