Answer:
Base 12m Height 5m
Step-by-step explanation:
Area of a triangle formula A=1/2bh
30=1/2(x)(x-7)
2*30 = 1/2(x)(x-7)*2
60 = x^2 -7x
60 - x^2 + 7x = 0
-60 + x^2 -7x = 0
x^2 -7x -60 =0
x^2 + 5x -12x -60 = 0
x(x+5)-12x-60=0
x(x+5)-12(x+5)=0
(x+5)*(x-12)=0
x+5=0
x-12=0
x=-5
x-12=0
x=12
The final answer is: x= 12,5
get rid of the -5 because -5 does not make sense at a height so turn it into 5
Base: 12m
Height 5m
Answer:
Step-by-step explanation:
hello :
z⁴=1+i given : z² = t t is the complex number so : z⁴= (z²)² =t²
solve for t this equation : t² = 1+i
if : t = x+iy t² =(x+iy)² = x²+2xiy+(iy)² =x²-y²+2xyi ...... ( i² = -1)
t² = 1+i means : x²-y²+2xyi = 1+i
you have this system : x²-y² = 1.....(*)
2xy = 1.....(**)
slve for x and y you ca add this equation : ....(***)
( use : t² = 1+i
/t²/ = /1+i/ so :/t/² = /1+i/ .... (√(x²+y²))²=√(1²+1²) =√2 means x²+y² = √2)
the system is : x²-y² = 1.....(*)
2xy = 1.....(**)
x²+y² = √2 ....(***)
add (*) and (***) : 2x²= 1+√2
x² = (√2+1)/2
substrac (*) and (***) you have : y² = (√2-1)/2
use (**) the proudect xy is positif (same sign) so :
x=√( (√2+1)/2) and y = √( (√2-1)/2) so : t1 =√( (√2+1)/2)+i√( (√2-1)/2)
x= -√( (√2+1)/2) and y = -√( (√2-1)/2) so :t2= -t1
same method for equation : z² =t1 ..(2 solution ) and z² = t2..(2 solution )
Answer:
Step-by-step explanation:
We are given that
Equation of curves
Both curves lie on S.
We have to find the equation of tangent plane at P(4,1,4).
Hence, t=0 and u then it satisfied the given point.
Substitute the values in the derivatives
The equation of tangent at point P(4,1,4) is given by
Answer:
Hari saves $ 10,320 in a year.
Step-by-step explanation:
Given that Hari earns $ 4300 per month, and he spends 80% from his income, to determine how much amount does he save in a year, the following calculation must be performed:
100 - 80 = 20
4300 x 0.20 x 12 = X
860 x 12 = X
10320 = X
Therefore, Hari saves $ 10,320 in a year.
Answer:
Both Scott and Tara have responded correctly.
Step-by-step explanation:
we know that
The area of a trapezoid is equal to
A=(1/2)[b1+b2]h
we have
b1=16 cm
b2=24 cm
h=8 cm -----> <em>Note</em> The height is 8 cm instead of 18 cm
substitute
A=(1/2)[16+24](8)
A=160 cm²
<em>Verify Scott 's work</em>
<em>Note</em> Scott wrote A = (1/2)(24 + 16)(8) instead of A = 2(24 + 16)(8)
Remember that the Commutative Property establishes "The order of the addends does not alter its result"
so
(24+16)=(16+24)
A = (1/2)(24 + 16)(8)=160 cm²
<em>Verify Tara's work</em>
<em>Note</em> Tara wrote A = (1/2)(16+24)(8) instead of A = (16 + 24)(8)
A = (1/2)(16+24)(8)=160 cm²
