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VladimirAG [237]
3 years ago
6

I am having trouble with the Inductive Step of the theorem below...

Mathematics
1 answer:
77julia77 [94]3 years ago
5 0

Answer:

I NEED HELP WITH THIS TOO ITS SUPER HARD

Step-by-step explanation:

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What is 20,880 × 2⁄5 = ?
gtnhenbr [62]

20,880*2/5

if im not mistaken i believe its 8.352

3 0
3 years ago
Read 2 more answers
Area=<br> Help please!! Asap thank u so much
Natasha_Volkova [10]

The area of the shaded region in the task content is; 251.2.

<h3>What is the area of the shaded region in the task content?</h3>

It follows from the task content that the area of the shaded region is;

= Area of semicircle IL - Area of semicircle JK + Area of semicircle IJ + Area of semicircle KL.

Hence, since the radius of each semicircle are as follows;

R(IL) = 12

R(IJ) = R(JK) = R(KL) = 4.

Hence, the Area of the shaded region can be evaluated as;

= (π/2)(12² - 4² + 4² +4²).

= π (144 +16)

= (3.14/2) × 160 = 251.2

Read more on Area of semicircle;

brainly.com/question/15822332

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6 0
2 years ago
Which number line shows the solution to the inequality n + 6 &lt; 4? ​
Anestetic [448]

Answer:

D) The very last one

Step-by-step explanation:

n + 6 < 4

n < -2

< means it's an open circle and goes in the LEFT direction

3 0
3 years ago
Solve the system of linear equations by substitution x-y=-4 2x+y=4
mylen [45]

Answer:

Given:

x-y=-4

2x+y=4

Step-by-step explanation:

x-y=-4

2x+y=4

add both the equation, we get

⇒  x-y=-4

  2x+y=4

⇒3x=-4+4

⇒3x=0

⇒x=0

∴ to find the value of y, put the value of x in any one equation

⇒x-y=-4

⇒0-y=-4

⇒-y=-4

⇒y=4

∴ x=0, y=4

3 0
3 years ago
Which of the following ordered pairs, when graphed on a standard
malfutka [58]
<h2><u>Answer:</u></h2><h2>\boxed{\boxed{\sf{(-2\frac{1}{3},\frac{1}{3})}}}</h2><h2 /><h2><u>Solution Steps:</u></h2>

______________________________

<h3>1.) First you need to graph all the ordered pairs:</h3>

(I have included the graph below)

<h3>2.) Then you determine which pairs are in the top left quadrant:</h3>
  • =(-2\frac{1}{3},\frac{1}{3})

So your answer is only \bold{(-2\frac{1}{3},\frac{1}{3})}.

______________________________

8 0
3 years ago
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