A pole-vaulter uses a 15-foot-long pile. She grips the pole so that the segment below her left hand is twice the length of the s
egment above her left hand. Her right hand grips the pole 1.5 above her left hand. How far up the pole is her right hand?
1 answer:
Let x + 1.5 be length of segment above left hand
Let 2x be length of segment below left hand
15 = x + 1.5 + 2x
15 = 3x + 1.5
15 - 1.5 = 3x
13.5 = 3x
13.5/3= 3x/3
4.5 = x
x = 4.5
This is the length above the left hand.
2x must be then 4.5*2 = 9 foot
This is the length below the left hand.
Checking
4.5 + 9 + 1.5 = 15 foot
Adding length below left hand & length of left hand to right hand:
9 + 1.5 = 10.5
The right hand is hence 10.5 foot far up the pole.
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