What is the product of (3y^-4)(sy^-4)?
2 answers:
You might be interested in
Answer:
Step-by-step explanation:
The equation of a periodic function is in the form:
y = Asin(Bx + C) + D
Where A = amplitude, B = 2π / period, D = vertical shift, phase shift = -C / B.
Given that:
amplitude: 4, period 4 phase shift = vertical shift = -2
Hence:
A = amplitude = 4, B = 2π / period = 2π / 4 = π / 2, D = vertical shift = -2.
Phase shift = -C / B
C = -phase shift * B = - * -2 * π / 2 = π.
Therefore substituting gives: