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2 years ago

Given a+2 when a=5 I need help

Mathematics

2 answers:

kow [346]2 years ago

6 0

The answer would be 7 so the top person is right :)

blsea [12.9K]2 years ago

3 0

Answer:

The answer to this is 7.

a+2

5+2

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A team from each school had 250 foam balls and a bucket. The Jackson team dunked 6 fewer balls than the Pine Street team. The Pi

lara [203]

478 because the pine dunked all but 8 so 250-8=242 then Jackson dunked 6 fewer so 242-6=236 then all together 242+236=478

4 0

3 years ago

Evaluate to one decimal place

ANTONII [103]

Answer:

<u>The correct answer is C. 1.6</u>

Step-by-step explanation:

Let's recall that e or Euler's number is a mathematical constant that is the base of the natural logarithm, in other words, the unique number whose natural logarithm is equal to one. The value of e is approximately 2.71828.

Now, replacing e, we have:

2.71828∧(1/2) = √2.71828 = 1.6 (Rounding to one decimal place)

<u>The correct answer is C. 1.6</u>

3 0

3 years ago

how many even numbers less than 1000 can be formed from the given digits 0,2,3,5; if repetition is not allowed ?

Lunna [17]

Answer: 2 numbers

Step-by-step explanation:

Since we are looking for even numbers, 0 and 2 must be the last number.

So if we have 0 at the end, there are 6 possibilities:

2350, 2530, 3250, 3520, 5230, 5320. None of these are less than 1000.

But, if we have 2 at the end, then we have 6 possibilities again:

0352, 0532, 3052, 3502, 5032, 5302. Only two of these are less than 1000.

So the only possibilities are 0350 and 0530, and so there are 2 possibilities.

8 0

2 years ago

Vanyuwa [196]

Step-by-step explanation:

4(2x-1)+3(2x+5)

8x-4+6x+15

8x+6x-4+15

14x+11

4 0

2 years ago

Read 2 more answers

The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge

Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

$5x+4y+5z=-1$

$x+y+2z=1$

$2x+y-z=-3$

Firs we find determinant of system of equations

Let a matrix A= $\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right]$ and B= $\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]$

$\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}$

$\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0$

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply $R_1\rightarrow R_1-4R_2$ and $R_3\rightarrow R_3-2R_2$

$\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]$

Apply $R_2\rightarrow R_2-R_1$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]$

Apply $R_3\rightarrow R_3+R_2$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]$

Apply $R_3\rightarrow- \frac{1}{2}$ and $R_2\rightarrow R_2-R_3$

$\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Apply $R_1\rightarrow R_1-R_3$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0

3 years ago