Answer:
Step-by-step explanation:
The cost of each Piano Lesson = $30
If there are x lessons, the total cost of lessons can be expressed as 30x.
Since the number of lessons cannot be negative, the value of x can be 0 or greater than 0, where x=0 shows no lesson.
For 1 lesson, x = 1
So the cost will be = 30(1) = $30
In ordered pair we can write it as (1, 30)
If we consider there is an option to attend half portion of a lecture, then for 1 and half lectures, x = 1.5
So, the cost for 1.5 lectures will be = 30(1.5) = $45
In ordered pair we can write it as (1.5, 45)
For 3 lesson, x = 3
The cost of 3 lessons will be = $90
In ordered pair we can write this as (3, 90)
So, from the given options, only following 2 ordered pairs satisfy the given conditions:
1) (1,30)
2) (3, 90)
(10c² +49cd+49d²) ÷ (5c+7d)
(5c+7d)(2c+7d) ÷ (5c+7d)
Delete (5c+7d)
= (2c+7d)
Answer:$17
Step-by-step explanation:
3 times 4 +5=$17.
(Answer does not include tax)
I'm assuming you meant to say
P(A) = 2/3
P(A and B) = 1/3
If that is the case, then A and B are independent if and only if the following equation is true
P(A and B) = P(A)*P(B)
So we multiply P(A) and P(B) to get the value of P(A and B). We don't know what P(B) is, but we can use algebra to find it
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P(A and B) = P(A)*P(B)
P(A)*P(B) = P(A and B)
(2/3)*P(B) = 1/3
P(B) = (1/3)*(3/2) .... multiply both sides by the reciprocal of 2/3
P(B) = (1*3)/(3*2)
<h3>P(B) = 1/2 is the answer</h3>
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If P(B) = 1/2, then
P(A and B) = P(A)*P(B)
P(A and B) = (2/3)*(1/2)
P(A and B) = (2*1)/(3*2)
P(A and B) = 1/3
Which is the given probability for both events happening. This confirms we have the correct P(B) value.