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Brums [2.3K]
3 years ago
15

*cough cough* I need help :D

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

Step-by-step explanation:

*cough cough*

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Rhombus JKLM is shown below. Find m∠KLM.
lianna [129]

Answer:

Option D

Step-by-step explanation:

Properties of a rhombus,

1). Diagonals of a rhombus bisect the opposite angles.

2). Sum of adjacent two angles of a rhombus is 180°.

By property (1),

Diagonal JL will bisect the angles ∠MJK and ∠KLM.

Therefore, m∠KLM = 2(5x + 3)°

Similarly, diagonal KM will bisect the angles ∠JKL and JML.

Therefore, m∠JKL = 2(9x - 11)°

By property (2),

2(9x - 11)° + 2(5x + 3)° = 180°

9x - 11 + 5x + 3 = 90

14x - 8 = 90

14x = 98

x = 7

Since, m∠KLM = 2(5x + 3)°

                        = 2(5×7 + 3)°

                        = 76°

Therefore, Option D will be the answer.

7 0
2 years ago
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adoni [48]

Answer:

Step-by-step explanation:

5\sqrt[3]{x+8}=35\\ \\ \sqrt[3]{x+8}=7\\ \\ x+8=7^3\\ \\ x+8=343

3 0
2 years ago
16(-4/3)<br> Please help me!!!
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I got -64/3 for this problem.
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The perimeter of a rectangular field is 344m.if the length of the field is 93m.what is it’s width?
snow_tiger [21]

Answer:

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Step-by-step explanation:

344-(93x2)=158

158/2=79m

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Step-by-step explanation:

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