Answer: Jim is <span>15 years old
Jim = 15 years old,
</span><span>Dad is 4 times as old as his son Jim = = 15 x 4 = 60
In 10 years, Jim = 15 + 10 =25 years old
Dad = 60 + 10 = 70
</span><span>Dad's age will be 20 years more than twice Jim's age
</span><span>
Dad's age = 20 + 2(25) = 70
</span>
1. distribute
step 1: 3 3
----- × X = ------X
5 5
3 5 3 Ima convert this into a decimal
------- × - ----- = - ------ ----> negative .375
5 8 8
2. write the problem now
3 1 7
----- X - 0.375 = ---- - X + ----
5 12 8
3. I would convert them into decimals and solve
0.6x - 0.375 = 0.08 - x + 0.875
+x +x
--------------------------------------------------
1.6x - 0.375 = 0.08 + 0.876
1.6x - 0.375 = 0.956
+0.375 +0.375
--------------------------------------------------
1.6x = 1.331
------ -------
1.6 1.6
---------------------------------------------------
x = 0.831875
rounded up : 0.83
Answer:
Step-by-step explanation:
multiplying fractions is usually super simple. You just multiply the top numbers and multiply the bottom numbers. So 2/3 * 5/7 = (2*5)/(3*7) = 10/21.
Here you have mixed fractions. For me, the easiest way is to make them improper fractions and then multiply them. So 2 and 3/4 becomes 11/4 and 1 and 13/20 becomes 33/20. Let me know if you don't get that.
Anyway, if we make the unknown fraction x we can rewrite this as an algebraic equation.
(11/4)x = 33/20 Now just multiply both sides by 4 and divide both sides by 11 and you will get
x = 3/5
Again, let me know if there's something you don't understand.
Complete question :
According to the National Association of Realtors, it took an average of three weeks to sell a home in 2017. Suppose data for the sale of 39 randomly selected homes sold in Greene County, Ohio, in 2017 showed a sample mean of 3.6 weeks with a sample standard deviation of 2 weeks. Conduct a hypothesis test to determine whether the number of weeks until a house sold in Greene County differed from the national average in 2017. Useα = 0.05for the level of significance, and state your conclusion
Answer:
H0 : μ = 3
H1 : μ ≠ 3
Test statistic = 1.897
Pvalue = 0.0653
fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.
Step-by-step explanation:
Given :
Sample size, n = 40
Sample mean, x = 3.6
Population mean, μ = 3
Standard deviation, s = 2
The hypothesis :
H0 : μ = 3
H1 : μ ≠ 3
The test statistic :
(xbar - μ) ÷ (s/√n)
(3.6 - 3) / (2/√40)
0.6 / 0.3162277
Test statistic = 1.897
Using T test, we can obtain the Pvalue from the Test statistic value obtained :
df = n - 1; 40 - 1 = 39
Pvalue(1.897, 39) = 0.0653
Decison region :
If Pvalue ≤ α ; Reject the null, if otherwise fail to reject the Null.
α = 0.05
Pvalue > α ; We fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.
Answer:
Follows are the solution to this questrion:
Step-by-step explanation:
In point a:
Nominal -scale
Qualitative -Variable
In point b:
Table of frequency
Frequency of results
early =22
On time =68
Late =7
Lost= 1
In point c:
Relative list of frequencies (about two decimal places)
Frequency of results
Early =0.23
On time =0.69
Late = 0.07
Lost = 0.01
In point d:
Early or early packing packets =92%
packages missing= 1%
