What? I’m really confused?
Answer:
the answer is 19.............
Answer:
look it up
Step-by-step explanation:
sorry for the bad answer.
Answer:
a) 0.06
b) 0.778
Step-by-step explanation:
Let's suppose a community of 100 families just to facilitate the calculation.
30% of the families own a dog
Dog = 30% of 100 = 30
20% of the families that own a dog also own a cat = 20% of 30 = 6
27% of all the families own a cat = 27% of 100 = 27
So, 6 families own a dog and a cat.
As 30 families own a dog, [30 - 6 =] 24 families own only dogs
As 27 families own a cat, [27 - 6 = ] 21 families own only cats
See picture attached.
a) What is the probability that a randomly selected family owns both a dog and a cat?
P(dog and cat) = dog ∩ cat/total = 6/100 = 0.06
b) What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
So, only cat/total cat
P (not dog|cat) = 21/27 = 0.778
To solve this problem, we must do a method of trial and error to find
for the next highest integer with exactly three factors. We know that the value
of k must be greater than 4, therefore by using trial and error to find for the
correct answer:
Factors of 5:1, 5
Factors of 6:1, 2, 3, 6
Factors of 7:1, 7
Factors of 8:1, 2, 4, 8
Factors of 9:1, 3, 9
Therefore we stop at 9 since this is already our answer. It has exactly
three factors.
The sum of the factors is:
sum of factors = 1 + 3 + 9
<span>sum of factors = 13</span>
