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AVprozaik [17]
3 years ago
14

A list of the entire population is​ called​ a(n):

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
6 0
The answer would be C.
Nesterboy [21]3 years ago
3 0

Answer: C

Step-by-step explanation:

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Someone answer this please it's for edguniety
KengaRu [80]
D = 171 - (61+53) = 171 -124 = 47
E = 171 - 90 = 81
A = 81 - (34+24) = 81 - 58 = 23
B = 61 - 23 = 38
C = 90 - (33+ 38) = 90 - 71 = 19

answer is B.
3 0
4 years ago
Which graph represents a linear function
valentina_108 [34]

Answer:

c on edge

Step-by-step explanation:

4 0
3 years ago
Umm so I'm confused<br> The question says<br> 5x - 2y = 24<br> x + 2y = 12
Anna007 [38]

Answer:

Step-by-step explanation:

5x-2y=24

x+2y=12

add the two equations

(5x-2y)+(x+2y)=24+12

6x=36

x=6

Plug in x=6 into any of the two equations

5(6)-2y=24

30-2y=24

-6= -2y

y= 3

x=6

y=3

(6,3)

6 0
3 years ago
4sin²<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D" id="TexFormula1" title="\frac{x}{2}" alt="\frac{x}{2}" align="absm
raketka [301]

Answer:

\displaystyle x=\left \{\frac{2\pi}{3}+2\pi k,\frac{4\pi}{3}+2\pi k, \frac{8\pi}{3}+2\pi k, \frac{10\pi}{3}+2\pi k\right \}k\in \mathbb{Z}

Step-by-step explanation:

Hi there!

We want to solve for x in:

4\sin^2(\frac{x}{2})=3

Since x is in the argument of \sin^2, let's first isolate \sin^2 by dividing both sides by 4:

\displaystyle \sin^2\left(\frac{x}{2}\right)=\frac{3}{4}

Next, recall that \sin^2x is just shorthand notation for (\sin x)^2. Therefore, take the square root of both sides:

\displaystyle \sqrt{\sin^2\left(\frac{x}{2}\right)}=\sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}}

Simplify using \displaystyle \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}:

\displaystyle \sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \frac{\sqrt{3}}{\sqrt{4}}=\pm \frac{\sqrt{3}}{2}

Let \phi = \frac{x}{2}.

<h3><u>Case 1 (positive root):</u></h3>

\displaystyle \sin(\phi)=\frac{\sqrt{3}}{2},\\\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}

Therefore, we have:

\displaystyle \frac{x}{2}=\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\frac{x}{2}=\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z},\\\\\begin{cases}x=\boxed{\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{4\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}

<h3><u>Case 2 (negative root):</u></h3>

\displaystyle \sin(\phi)=-\frac{\sqrt{3}}{2},\\\phi = \frac{4\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{5\pi}{3}+2\pi k, k\in \mathbb{Z},\\\begin{cases}x=\boxed{\frac{8\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{10\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}

8 0
2 years ago
I need help this is due tomorrow
goldfiish [28.3K]

Answer:

x z y is the awnser

Step-by-step explanation:

I'm doing this type of stuff

8 0
3 years ago
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