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qaws [65]
3 years ago
14

Select all the expressions that are greater than 1.

Mathematics
1 answer:
anygoal [31]3 years ago
3 0

Answer:

Expressions greater than 1 are:

5 \div  \frac{9}{10}

2 \frac{3}{2}  \div  1\frac{3}{5}

Step-by-step explanation:

5 \div  \frac{9}{10}

= 5 \times  \frac{10}{9}

=  \frac{50}{9}

= 5.55

___________________________________________

=  \frac{3}{5}  \times  \frac{1}{6}

=  \frac{1}{5}  \times  \frac{1}{2}

=  \frac{1}{10}

= 0.1

________________________________________

\frac{4}{5}  \div  \frac{3}{7}

=  \frac{4}{5}  \times  \frac{3}{7}

=  \frac{12}{35}

________________________________________

2 \frac{3}{5} \div 1 \frac{3}{5}

=  \frac{13}{5}  \div  \frac{8}{5}

=  \frac{13}{5}  \times  \frac{5}{8}

=  \frac{13}{8}

= 1 \frac{5}{8}

________________________________________

\frac{12}{5}  \div  \frac{13}{5}

=  \frac{12}{5}  \times  \frac{5}{13}

=  \frac{12}{13}

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3 years ago
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3 years ago
What is 4(5n-7)=10n+2?variables on both sides
forsale [732]

Example:

About "Solving equations with variables on both sides"

Solving equations with variables on both sides :

To solve equations with variables on both sides, we have to bring the variables to the left side of equal sign and the numbers which or not having the variables, that is constants to the right side of equal sign.

Solving Equations with Variables on Both Sides - Steps

Step 1 :

Use the Distributive Property to remove the grouping symbols.

Step 2 :

Simplify the expressions on each side of the equals sign.

Step 3 :

Use the Addition and/or Subtraction Properties of Equality to get the variables on one side of the equals sign and the numbers without variables on the other side of the equals sign.

Step 4 :

Simplify the expressions on each side of the equals sign.

Step 5 :

Use the Multiplication or Division Property of Equality to solve.

If the solution results in a false statement, there is no solution of the equation.

If the solution results in an identity, the solution is all numbers.

Solving Equations with Variables on Both Sides -Examples

Example 1 :

Solve the following equation. Then check the solution.

5t - 9  =  -3t + 7

Solution :

5t - 9  =  -3t + 7

In order to get rid of -3t, we have to add 3t on both sides.

5t + 3t - 9  =  -3t + 3t + 7

8t - 9  =  7

In order to get rid of -9, add 9 on both sides

8t - 9 + 9  =  7 + 9

8t  =  16

Divide by 8 on both sides

8t/8  =  16/8

t  =  2

Hope this helps you understand better!

(It is not the answer but it is an example so hope this helps and please give me Brainliest)

3 0
4 years ago
What is the answer to it
andre [41]

No question?

Why not add one!

4 0
3 years ago
The area of a playground is 216 yd^2. The width of the playground is 6 yd longer than its length. Find the length and width of t
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Let the length of the playground be x, then the width is 6 + x.

Area = length * width = x * (6 + x) = 6x + x^2 = 216

Solving the quadratic equation x^2 + 6x - 216 = 0, we have x = 12 or -18

i.e length = 12 and width = 6 + 18 = 18

5 0
3 years ago
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