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lubasha [3.4K]
3 years ago
13

A trader buys two July futures contracts on frozen orange juice. Each contract is for the delivery of 15,000 pounds.The current

futures price is 120 cents per pound, the initial margin is $6,000 per contract, and the maintenance margin is $4,500 per contract. What price change would lead to a margin call
Business
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

1.10 dollars or 110 cents

Explanation:

We have a fall in the balance margin by contract.

We calculate the change as:

-1,500 =[ future price - (1.20)]*15000

We got 1.20 by dividing 120 by 10.

-1500 = [future price - (1.20)]*15000

Divide through by 15000

-1500/15000 = future price - 1.20

-0.10 = future price -1.20

Collect like terms

-0.10+1.20 = future price

1.10 = future price

Therefore the margin is $1.10 or 110 cents

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B. the pain of losing $1,000 on a bet exceeds the pleasure of winning $1,000 on a bet.

Explanation:

A risk averse person is an individual or person rather who prefers lower returns with known risk than higher returns with unknown or higher risks. In this case, the individual prioritizes preservation of capital at hand over the potential of a more than average return. In this scenario, for a risk averse individual, the pain of losing $1,000 on a bet exceeds the pleasure of winning $1,000 on a bet based on the high uncertainty attached to winning the $1000 bet.

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Ann, Bob, Carl, and Dan are randomly lined up. The first two players in line then play a game; the winner of that game plays a g
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Explanation:

The probability of Ann winning the prize can be analysed as potray below

1.pr(of Ann being the first player selected).

Here Ann plays the 2nd,3rd and 4th player to win prize,the probability=0.8×0.8×0.8=0.512

2.Pr(of Ann being the second player selected)

If Ann is randomly selected as the second player,she will still need to play three matches to win with 1st,3rd and 4th

0.8×0.8×0.8=0.512

3.Pr(of Ann. Being the third player chooses randomly),Ann will get to play just two players i.e the winner of 1and 2 and the 4th.the probability=0.8×0.8=0.64

4.Pr(of Ann being the 4th player choosen randomly)

Ann gets to play only one match to win the prize in this scenario

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Total probability a Ann winning the prize=0.512+0.512+0.64+0.8=2.464

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In 2013, Space Technology Company modified its model Z2 satellite to incorporate a new communication device. The company made th
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Answer:

1. Dec 31

Dr Research and Development Expense $3,180,000

Cr 2013 Patent $3,180,000

2. Dec 31

Dr Equipment $60,000

Cr 2013 Patent $60,000

3. Dec 31

Dr Research and Development Expense $10,000

Cr 2013 Accumulated Depreciation - Equipment $10,000

Explanation:

1. Preparation of the Journal entry to Record the correcting entry to expense

Dec 31

Dr Research and Development Expense $3,180,000

Cr 2013 Patent $3,180,000

(Being To record research and development expense )

Calculation for the Total amount of theresearch and development expense

Basic research to develop the technology $2,000,000

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Development of a prototype device $300,000

Testing and modification of the prototype $200,000

TOTAL research and development expense $3,180,000

2. Preparation of the journal entry to Record the correcting entry to capitalize the cost of equipment

Dec 31

Dr Equipment $60,000

Cr 2013 Patent $60,000

(Being To correct cost of equipment capitalized to patent)

3. Preparation of the Journal entry to Record the correcting entry to record depreciation on equipment

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Dr Research and Development Expense $10,000

Cr 2013 Accumulated Depreciation - Equipment $10,000

(Being To record research and development expens

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