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My name is Ann [436]
3 years ago
6

If 6 x 7 = 26 +0, find the number that belongs in the box. 211

Mathematics
1 answer:
Blababa [14]3 years ago
3 0
Answer: 185 sorry if wrong
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The value of a professional basketball player's autograph rose 40% in the last year. It is now worth $364.00. What was it worth
Olin [163]
F it rose 10% that means that it is now worth 110% of what it was a year ago. So set up an equation: 297 = 110% of x297 = 1.1 x270 = x So it was worth $270 a year ago.
4 0
3 years ago
(x+2)(x+5) find the following products by using distributive property
nika2105 [10]

Answer:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

(

x

+

5

)

(

x

+

2

)

becomes:

(

x

×

x

)

+

(

x

×

2

)

+

(

5

×

x

)

+

(

5

×

2

)

x

2

+

2

x

+

5

x

+

10

We can now combine like terms:

x

2

+

(

2

+

5

)

x

+

10

x

2

+

7

x

+

10

Step-by-step explanation:

7 0
3 years ago
You draw one card from a? 52-card deck. then the card is replaced in the deck and the deck is? shuffled, and you draw again. fin
Solnce55 [7]

there are 4 tens in a deck so probability of picking a ten is 4/52 reduced to 1/13

 there are 13 clubs in a deck, probability for that is 13/52 reduced to 1/4

probability for both is 1/13 x 1/4 = 1/52

6 0
3 years ago
shanes neighbor pledged 1.25 for every 0.5 miles that shane swims in the charity swim-a-thon.if Shane swims 3 miles,how much mon
Paraphin [41]
3/0.5 = 6
6 x 1.25 = 7.50
4 0
3 years ago
Read 2 more answers
“ write all your answers with a positive exponent so your answer will be in the form of x^# or 1/(x^#)
gayaneshka [121]

Answer:

Step-by-step explanation:

5). \frac{1}{x^{-9}} = \frac{1}{\frac{1}{x^9} }

     = x^{9}

6). \frac{1}{x^{-2}}=\frac{1}{\frac{1}{x^2} }

      = x²

7). x^{-6}=\frac{1}{x^6}

8). \frac{1}{x^{-7}}=\frac{1}{\frac{1}{x^7} }

           = x^{7}

9). x^{-8}=\frac{1}{x^8}

10). \frac{1}{x^{-3}} = \frac{1}{\frac{1}{x^{3}}}

            = x³

7 0
2 years ago
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