Given/equations formed from text:
I: l=w+3
II: A=l*w
III: new area B=(l-2)*w
IV: B=A-30
substitute l in II with I to remove l:
II': A=l*w=
(w+3)*w=
w^2+3w
substitute l in III with I to remove l:
III': B=(l-2)*w=
(w+3-2)*w=
(w+1)*w=
w^2+w
substitute A and B from II' and III' into IV:
B=A-30
w^2+w=w^2+3w-30
30=2w
w=15
insert w=15 into I:
l=15+3=18
->
A) dimensions of full size rectangle are width 15 and length 18
dimensions of reduced size rectangle are width 15 and length 16
B) full size: 15*18=10*18+5*18=180+90=270cm^2
reduced size: 15*16=10*16+5*16=160+80=240cm^2
Answer:
log_(32)8= 3/5
Step-by-step explanation:
Log_(32)8 = m
write is as
32^m=8
(2^5)^m = 2^3
2^5m = 2^3
Since the bases are the same, then two expressions are only equal if the exponents are also equal.
5m = 3
divide 5 on both sides to remove it from m
m= 3/5
Hope this helps!
.........................
A) Y1-Y2/X1-X2
9-4/8-(-2) = 5/10= 1/2
b) 1/2x+b=y <-- plug in a point
1/2(-2)+b=4 <--plugged in (-2,4)
-1+b=4 <-- simplify/solve
b=5
c) 1/2x+5=y
Answer:
8x+2
Step-by-step explanation:
8x+4/2
= 8x+2
because 2 cancel out 4
and because they are not like terms
the answer will be 8x+2
