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valina [46]
3 years ago
7

The distance around a circular region is known as its________​

Mathematics
1 answer:
aivan3 [116]3 years ago
3 0

Answer:

Circumference.

Step-by-step explanation:

The distance around a circle is its circumference.

The distance around a circular region is known as its CIRCUMFERENCE.

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Step-by-step explanation:

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maks197457 [2]

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11 1/5

Step-by-step explanation:

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Can you please explain this?​
Leni [432]

Answer:

The question is giving you pairs of points in space which can be used to define lines. It is then asking you to determine if the lines defined by those points are parallel, perpendicular, or neither.

Step-by-step explanation:

Two key things you need to know to solve this is that the lines will be parallel if their slopes are the same, and perpendicular if one slope is the negative reciprocal of the other (i.e. s_{1} = -s_{2}^{-1})

Let's start with question 11. You are given two pairs of points, each of which describes a distinct line:

(3,5)-(1,1) and (0, 2)-(5, 12)

To find the slope of each pair, take the vertex with the lesser x co-ordinate, and subtract it from the vertex with the greater x co-ordinate.  That will give us a valid Δx and Δy to get the slope.

In the first pair, 3 > 1, so we'll subtract the second point from the first:

s = \Delta y / \Delta x\\s = \frac{5 - 1}{3 - 1}\\s = 4/2\\s = 2

So the first pair of vectors describe a line with a slope of 2.  Let's look at the other pair:

s = \Delta y / \Delta x\\s = (12 - 2) / (5 - 0)\\s = 10 / 5\\s = 2

That also gives us a slope of 2, meaning that the two lines are parallel.

This same process will need to be done for the other three questions.  We can't answer questions 12 or 14 here, as the last point is cut off on the edge of the image.  For question 3 though, one line has a slope of 7/3, and the other 3/7. That puts them in the "neither" category, as one is not the negative reciprocal of the other, but instead the positive reciprocal.

6 0
3 years ago
Please help fast
Vladimir79 [104]

Answer:

  B:  II, IV, I, III

Step-by-step explanation:

We believe the proof <em>statement — reason</em> pairs need to be ordered as shown below

  Point F is a midpoint of Line segment AB Point E is a midpoint of Line segment AC — given

  Draw Line segment BE Draw Line segment FC — by Construction

  Point G is the point of intersection between Line segment BE and Line segment FC — Intersecting Lines Postulate

  Draw Line segment AG — by Construction

  Point D is the point of intersection between Line segment AG and Line segment BC — Intersecting Lines Postulate

  Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH — by Construction

__

  II Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC — Midsegment Theorem

  IV Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC — Substitution

  I BGCH is a parallelogram — Properties of a Parallelogram (opposite sides are parallel)

  III Line segment BD ≅ Line segment DC — Properties of a Parallelogram (diagonals bisect each other)

__

  Line segment AD is a median Definition of a Median

3 0
3 years ago
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