Answer:
2x^2*(2x^3+8x^2+2x) or
4x^5+16x^4+4x^3
Step-by-step explanation:
A=[2x^3-x+(8x^2+3x)]*4x^2/2=2x^2*(2x^3+8x^2+2x)
or A=4x^5+16x^4+4x^3
Either 1, or 2, smart ppl help!
Y/5 im guessing thats the answer if you need it into number form
If you use the elimination method, add both equations together to eliminate a variable. You will get 5x=15. x=3. Replace x in the equations with 3 to get y =7, so your answer is A, (3,7.) I hope his helped!. Please give brainliest!
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} .
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = -1, b = 2 and c = 1.
Next step is to plug in these values in the above formula. Therefore,







So, x =