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d1i1m1o1n [39]
3 years ago
13

I NEED TO KNOW THIS Q

Mathematics
2 answers:
Nikolay [14]3 years ago
6 0

See picture for explanation.

IRISSAK [1]3 years ago
3 0
To find where they intersect you need to find where they equal each other. Since you already know what y equals in terms of x from the blue equation you can plug that into the red equation to solve for x
x + 4(2x - 6) = 12 \\ x + 8x - 24 = 12 \\ 9x = 36 \\ x = 4
Now that we know what x is equal to we can plug it into the blue equation to solve for what y is equal to
y = 2(4) - 6 \\ y = 8 - 6 \\ y = 2
The place where the two lines intersect is at the coordinate (4,2)
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Julli [10]

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30 + 25 = 55

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Multiply total price by 4/5:

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In complete two or more sentences, determine the appropriate model for the given data and explain how you made your decision. (1
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2 years ago
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Hunter-Best [27]

Let's simplify the following expression:

\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}

We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

4 0
1 year ago
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