Answer:
-1.375
Step-by-step explanation:
A square, rectangle, rhombus (I think)
Answer:
Let L be the length of the rectangle and w be the width of the rectangle.
"The lenght of a rectangle is one less than twice the width" means L=2W-1
Using perimeter formula of a rectangle which is P=2(L+W) you have:
P=2(L+W)
130=2(2W-1+W)
Solve equation above to find W
130=2(3W-1)
130=6W-2
130+2=6W
132=6W
W=22
From here you find L=2W-1=2x22-1=43
Only thing left is to find area A=LxW
I believe the answer is C.
S(p)=D(p)
400-4p+0.00002p4=2,800-0.0012p3
Solve for p
P=96.24